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Arlecino [84]
3 years ago
9

Satellite a has an orbital radius 3.00 times greater than that of satellite

Physics
1 answer:
ozzi3 years ago
3 0
Thank you for posting your question here at brainly. Below is the solution:

To find the circumference (orbit) of an object, you use Pi x Diameter. 
<span>As you have the circumference of B, you divide it by Pi to get the Diameter. </span>
<span>So 120 divided by 3.141592654 = 38.2 minutes for the Diameter. </span>

<span>As' radius and Diameter will be 3x greater than B. </span>
<span>38.2 x 3 = 114.6 </span>
<span>To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes. </span>
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A dragster starts from rest and travels 1/4 mi in 6.80 s with constant acceleration. What is its velocity when it crosses the fi
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<h2>Its velocity when it crosses the finish line is 117.65 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Time, t = 6.8 s    

        Displacement, s = 1/4 mi =    400 meters

     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.8 + 0.5 x a x 6.8²

                      a = 17.30 m/s²

Now we have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = ?

     Time, t = 6.8 s

      Acceleration, a = 17.30 m/s²

     Substituting

                      v = u + at  

                      v = 0 + 17.30 x 6.8

                      v = 117.65 m/s

Its velocity when it crosses the finish line is 117.65 m/s

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