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2 years ago

What is machinery............

1 answer:

8 0

an assemblage of machines or mechanical apparatuses: the machinery of a factory. the parts of a machine, collectively: the machinery of a watch. a group of people or a system by which action is maintained or by which some result is obtained: the machinery of government.

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when an object is placed near a concave mirror, at what position does it forms a magnified and erect image.

alexira [117]

Answer:

Between the principal focus and the pole of the mirror

4 0

2 years ago

A small, 300 g cart is moving at 1.20 m/s on an air track when it collides with a larger, 2.00 kg cart at rest?

stiv31 [10]

Answer:

The speed of the large cart after collision is 0.301 m/s.

Explanation:

Given that,

Mass of the cart, $m_1 = 300\ g = 0.3\ kg$

Initial speed of the cart, $u_1=1.2\ m/s$

Mass of the larger cart, $m_2 = 2\ kg$

Initial speed of the larger cart, $u_2=0$

After the collision,

Final speed of the smaller cart, $v_1=-0.81\ m/s$ (as its recolis)

To find,

The speed of the large cart after collision.

Solution,

Let $v_2$ is the speed of the large cart after collision. It can be calculated using conservation of momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$m_1u_1+m_2u_2-m_1v_1=m_2v_2$

$v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}$

$v_2=\dfrac{0.3\times 1.2+0-0.3\times (-0.81)}{2}$

$v_2=0.301\ m/s$

So, the speed of the large cart after collision is 0.301 m/s.

4 0

2 years ago

An object moves in one dimension according to the function x(t)=13at3, where a is a positive constant with units of ms3. During

9966 [12]

Answer:

B) 1/5 ba^2 T^5

Explanation:

The dissipated energy is given by the work done over the object by the force F=-bv. The work is given by the following formula:

$dW=Fdx$

you derivative the function f(x) and replace v by the derivative dx/dt you obtain:

$v=\frac{dx}{dt}=at^2\\\\dx=at^2dt\\\\W=\int_0^{T} Fdx=-\int_0^Tvbdx=-\int_0^Tb(at^2)(at^2dt)\\\\W=-ba^2\frac{T^5}{5}=-\frac{1}{5}ba^2T^5$

hence, the dissipated energy is 1/5 ba^2 T^5

7 0

3 years ago

To calculate lobe lift, you need to know the _______ diameter and the lobe height

svetoff [14.1K]

The answer is the diameter of the cam shaft.

This is used to compute for the area of the circle so you can multiply it with the rocker ratio to get maximum amount of weight the valve can lift.

5 0

2 years ago

Read 2 more answers

A car is moving at a constant 34 m/s for 7 seconds. What is the average acceleration of the car?

Marina86 [1]

Since the body is moving with uniform motion therefore the body doesn't accelerate
therefore acceleration is 0m/s^2

7 0

2 years ago

What is machinery............​

What is machinery............