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REY [17]
3 years ago
5

What is the sum LA OA. 12 O B. oc. o OD. -12

Mathematics
2 answers:
Kitty [74]3 years ago
7 0

Answer:

Step-by-step explanation:

O-ber-on'-l-a ' Od-on-tos-o'-rl-a Om-phaY-i—a Ob-e'-sT-a l Od-on-tos-per'-mum Om-phal-ob'J-um ob-e'-sum od-o'-ra* Om-phal-oc-oc'-ca ob-fus-ca'-ta od-o-ra'-ta ... oc-ul-a'-tus I ol-ig-ot'-rich-um Op-loth-e'-oa Oc'-ul-us ol-it-0'-rI-a Op-op'~on-ax ... in r12'-ler; y as I; y as i; as, w, ei, as m' in pain; an as ou- in house; g, c, and oh, ...

AlladinOne [14]3 years ago
3 0

Answer:I dont think this is a question

Step-by-step explanation:

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Graphs of the following equations are straight lines except :
meriva

Answer:

D.

Step-by-step explanation:

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Use the sample data and confidence level given below to complete parts​ (a) through​ (d). A drug is used to help prevent blood c
Alla [95]

Answer:

a) \hat p=\frac{148}{4167}=0.036

b) 0.0355 - 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.030

0.0355 + 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.041

Step-by-step explanation:

The sample proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part a

The estimated proportion for this case can be calculated like this:

\hat p=\frac{148}{4167}=0.036

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing we got:

0.0355 - 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.030

0.0355 + 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.041

8 0
4 years ago
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