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3 years ago

What is the sum LA OA. 12 O B. oc. o OD. -12

Mathematics

2 answers:

Kitty [74]3 years ago

7 0

Answer:

Step-by-step explanation:

O-ber-on'-l-a ' Od-on-tos-o'-rl-a Om-phaY-i—a Ob-e'-sT-a l Od-on-tos-per'-mum Om-phal-ob'J-um ob-e'-sum od-o'-ra* Om-phal-oc-oc'-ca ob-fus-ca'-ta od-o-ra'-ta ... oc-ul-a'-tus I ol-ig-ot'-rich-um Op-loth-e'-oa Oc'-ul-us ol-it-0'-rI-a Op-op'~on-ax ... in r12'-ler; y as I; y as i; as, w, ei, as m' in pain; an as ou- in house; g, c, and oh, ...

AlladinOne [14]3 years ago

3 0

Answer:I dont think this is a question

Step-by-step explanation:

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4 years ago

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meriva

Answer:

Step-by-step explanation:

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3 years ago

Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood c

Alla [95]

Answer:

a) $\hat p=\frac{148}{4167}=0.036$

b) $0.0355 - 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.030$

$0.0355 + 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.041$

Step-by-step explanation:

The sample proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

The estimated proportion for this case can be calculated like this:

$\hat p=\frac{148}{4167}=0.036$

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing we got:

$0.0355 - 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.030$

$0.0355 + 1.96\sqrt{\frac{0.036(1-0.036)}{4167}}=0.041$

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4 years ago