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Ratling [72]
4 years ago
9

Solve the system of equations

Mathematics
1 answer:
Valentin [98]4 years ago
4 0
x-4y=5 \ \ \ |\hbox{multiply both sides by (-1)} \\
x-3y=2 \\ \\
-x+4y=-5 \\
\underline{x-3y=2 \ \ \ \ \ \ } \ \ \ |\hbox{add the sides of the equation} \\
-x+4y+x-3y=-5+2 \\
4y-3y=-5+2 \\
y=-3 \\ \\
\hbox{replace y with -3 in one of the equations and solve for x:} \\
x-4y=5 \\
x-4 \times (-3)=5 \\
x+12=5 \\
x=5-12 \\
x=-7 \\ \\
(x,y)=(-7,-3)
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F(x) = 3x + 21; solve for f(3) and f(7)
Inessa [10]

Answer:

Step-by-step explanation:

Given that f(x) = 3x + 21

Plug in 3 for x

F(3)= 3(3) +21

F(3) = 9+21

f(3) = 30

Plug in 7 for x

F(7)= 3(7) +21

F(7) = 21+21

f(7) = 42

7 0
3 years ago
Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'
aleksandr82 [10.1K]

Answer:

A. △P'Q'R' does not equal △P''Q''R''.

B. Reflecting across UT would change the orientation of the figure.

C. The sequence does not include a reflection that exchanges U and S.

D. Rotating about point U is not a rigid motion because it changes the orientation of the figure.

E. Translating point R' to Q' is a non-invertible transformation because it changes the location of P'.

(D) Rotating about U is not a rigid motion because it changes the orientation of the figure. [I think D is an incorrect answer choice.]

Step-by-step explanation:

Proof No.1

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R' about point U to get △P''Q''R''. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

Proof No.2

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R about point U to get △P''Q''R'' so that R''Q'' and UT coincide. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

8 0
3 years ago
5 : 2 : 11 =.... : 6 : ....
lubasha [3.4K]
5:2:11=15:6:33
Multiply by 6/2=3
7 0
3 years ago
This one is number 6
iren2701 [21]
I’m not entirely sure, but i do think it could be B.
5 0
2 years ago
Read 2 more answers
On a recent math test, Samantha scored 3 points for each of the 18 multiple choice questions she
Crazy boy [7]

The required expression will therefore be:

(3×18) + (5×6) + 4

Her total score is 88points :

From the question given, we are told that Samantha scored 3 points for each of 18 multiple choice questions, this means that the total points made here is expressed as:

(3 × 18) ...1

If she got 5 points for each of the 6 short response questions she answered

correctly, the total point made will be expressed as;

(5×6) ... 2

Total score for an additional 4 points for the bonus question will be "4"

Expression for her total score will be the sum of all the expression above as thus:

(3×18) + (5×6) + 4

Taking the sum, her score will be:

= (3×18) + (5×6) + 4

= 54 + 30 + 4

= 84 + 4

= 88 points

The required expression will therefore be:

(3×18) + (5×6) + 4

Her total score is 88points

Learn more about sum here: brainly.com/question/16397188

7 0
3 years ago
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