0.53313648 feet = 16.25cm
GaBr3
Gallium=Ga
Bromine= Br
Bromide=Br3
There's 6.022×10^23 particles in 1 mole of anything
like there is 1000 grams in 1 kilogram of anything
It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.
<u>Explanation:</u>
2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂
We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

= 337.5 g AgCl
In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.
It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.
Hi there
In order for an electron to jump into a higher energy state, it must first absorb energy (heat, light, etc).
When an electron goes back down to the ground state from the excited state, it emits energy usually in the form of a photon.
i hope this helps