1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
creativ13 [48]
4 years ago
9

Are silver spoons tarnished and turned black, chemical or physical property?

Chemistry
1 answer:
zavuch27 [327]4 years ago
4 0
He ability to rust is a chemical property of iron. The metal silver does not rust, but eventually a darker substance called tarnish forms on its surface. The chemical properties of copper cause it to become a blue-green color when it is exposed to air
You might be interested in
#PLATOFAM
Vsevolod [243]
Ketones and aldehydes are simple compounds that contain a carbonyl group (a carbon-oxygen double bond). They are considered "simple" because they do not have reactive groups like −OH or −Cl attached directly to the carbon atom in the carbonyl group, as in carboxylic acids containing −COOH<span>.

So your answer would be D.).

I hope that this helps. :)</span>
4 0
3 years ago
Read 2 more answers
What was the result of collisions between the early Earth and other, smaller protoplanets?
RoseWind [281]

The trajectory of their motion knocked the Earth into a different orbit.

3 0
4 years ago
Use the reaction given below to solve the problem that follows: Calculate the mass in grams of aluminum oxide produced by the re
bearhunter [10]

Answer:  28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}   

\text{Moles of} Al=\frac{15.0g}{27g/mol}=0.556moles

The balanced chemical equuation is:

4Al+3O_2\rightarrow 2Al_2O_3  

According to stoichiometry :

4 moles of Al produce == 2 moles of Al_2O_3

Thus 0.556 moles of Al will produce=\frac{2}{4}\times 0.556=0.278moles  of Al_2O_3

Mass of Al_2O_3=moles\times {\text {Molar mass}}=0.278moles\times 102g/mol=28.4g

Thus 28.4 g of aluminum oxide is produced by the reaction of 15.0 g of aluminum metal.

7 0
3 years ago
A man weighing 48 N climbs 82.0 meter ladder how much work is done
Karolina [17]

Heeeyyyyyyyy........

3 0
3 years ago
Determine the AMOUNT OF NO2, LIMITING REACTANT, AND THE AMOUNT AND NAME OF EXCESS REACTANT.
zepelin [54]

Answer:

balanced equation mole ratio 5 2 mol NO/1 mol O2

10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2

20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO

actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2

Because the actual mole ratio of NO:O2 is larger than the balanced equation mole

ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.

Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO

0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO

Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2

Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N

Explanation:

3 0
3 years ago
Other questions:
  • The solubility of three compounds in water is shown in the table above. What best explains the observations shown in the table?
    8·2 answers
  • Which best describes the effect of jj Thomson discovery
    7·1 answer
  • Jill then wrote the formulas for all the possible compounds that sodium can form with the other ions. What formulas did she writ
    10·1 answer
  • What should go in the blank?
    14·1 answer
  • The fact that a heat pump requires energy to move heat from a colder object (the outside of a house) to a hotter object (the ins
    12·1 answer
  • Atomic Size: Determine which of the following element pairs is the larger one
    9·1 answer
  • Calculate the amount of copper (in moles) in a 45.2 g pure copper sheet
    11·1 answer
  • A
    12·1 answer
  • 4. How many joules of heat are absorbed to raise
    13·1 answer
  • 2. The enthalpy (heat) of hydration of a soluble ionic compound such, as KCl, is
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!