Answer:
The molar average velocity is 0.0588 cm/s
The N₂ diffusion velocity relative to the mole average velocity is -0.1428 cm/s
The molar diffusional flux of N₂ is -3.9x10⁻³
Explanation:
Given data:
T = temperature = 265 K
O₂ = 25%
N₂ = 60%
CO₂ = 15%
vO₂ = -0.084 cm/s
vN₂ = 0.12 cm/s
vCO₂ = 0.052 cm/s
The molar average velocity is equal:
The N₂ diffusion velocity relative to the molar average velocity is:
The molar diffusional flux of N₂ is:
C3H8 + 5O2 ------> 3CO2 + 4H2O
from reaction 1 mol 5 mol
given 1.82 mol x mol
x=(1.82*5)/1 = 9.10 mol CO2
Answer:
Explanation:
Boyle's law for gases states that, at constant temperature, the volume and pressure of a fixed amount of gas are inversely related.
Mathematically, that is:
Here, you have:
Then, you can solve for V₂:
Substitute and compute:
- V₂ = 14.1 KPa × 2.4L / 84.6 KPa = 0.40 L ← answer
Moles of ca3(po4)2 = 23.7 / 310.17 = 0.076
moles of (PO4)3- = 0.076 x 2 = 0.152
now, no. of ions = 0.152 x 6.022 x 10^{23}
= 9.2 x 10^{22}
