Answer: 9 7/12
TO simplify the answer make common denominator which would be 12 so 5/6 times 2 on each 10/12 & 3/4 x3 becomes 9/12 so those make 1 7/12 add with 1 and 7
Te difference of 2 standard deviation of a population n1 & n2 is given by the formula:
sigma (difference)=√(sigma1/n1 + sigma2/n2), Plug:
sigma(d)= √(49/100 + 36/50)
Sigma(d=difference) =1.1
Answer:
the traingle that have 0 reflectional is the scalene traingle then its number one all defferent sides
give me brainliest if it true
Answer:
The sum of vectors is <5,2>.
Step-by-step explanation:
The given vectors are <-1,4> and <6,-2>.
We need to find the sum of the given vectors and illustrate geometrically.
Plot the point (-1,4) on a coordinate plane and draw a vector <a> from (0,0) to (-1,4).
Plot the point (6,-2) on a coordinate plane and draw a vector <b> from (0,0) to (6,-2).
Now complete the parallelogram and the diagonal represents the sum of both vectors.
The end point of the diagonal is (5,2). It means sum of vectors is <5,2>.
Check the sum of vectors:

Therefore, the sum of vectors is <5,2>.
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The correct answers are:</span><span>
(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0
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Explanation:</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.
Rational Function = g(x) = </span></span>

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Denominator = x = 0
Hence the vertical asymptote is x = 0.
(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:
Given function = g(x) = </span>

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We can write it as:
g(x) = </span>

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If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.
In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
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