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3 years ago

Explain why the motto "Do whatever it takes to win!" may not be an ethical guideline to follow.

Physics

2 answers:

Murrr4er [49]3 years ago

4 0

If you did this then it could lead to cheating or someone else getting hurt.

Karolina [17]3 years ago

3 0

Be selfish is pretty much what its telling you

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One long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along

strojnjashka [21]

Answer:

y = -0.42 m

1.16*10^-4 T(-k)

-1.73*10^4 N/C (j)

Explanation:

(a) Above the pair of wires, The field out of the page of the 50 A current will be stronger than the (—k) field of the 30 A current (k).

Between the wires, both produce fields into the page.

below the wires, y = - | y |

B = u_o*I/2πr (-k) + u_o*I/2πr (k)

0 = u_o/2πr[50/ | y |+0.28 (-k) + 30/| y | (k) ]

50 | y | = 30(| y | + 0.28)

| y | = -y

-50 y = 30*(0.28 - y)

y = -0.42 m

b) B = u_o*I/2πr (-k) + u_o*I/2πr (k)

B = 4π*10^-7/2π[ 50/0.28 -1 (-k) +30/1(-k) ]

= 1.16*10^-4 T(-k)

F = qv*B

F = (-2*10^-6)*(150*10^6(i) )(1.16*10^-4(-k))

F = 3.47*10^-2 N(-j)

c) F_e = qE

E = F_e/q

E = 3.47*10^-2/-2*10-6

= -1.73*10^4 N/C (j)

7 0

4 years ago

A 1750-kilogram cars travels at a constant speed of 15.0 meters per second around a horizontal, circular track with a radius of

bulgar [2K]

m = mass of the car moving in horizontal circle = 1750 kg

v = Constant speed of the car moving in the horizontal circle = 15 m/s

r = radius of the horizontal circular track traced by the car = 45.0 m

F = magnitude of the centripetal force acting on the car

To move in a circle . centripetal force is required which is given as

F = m v²/r

inserting the above values in the formula

F = (1750) (15)²/(45)

F = (1750) (225)/(45)

F = 1750 x 5

F = 8750 N

6 0

3 years ago

Marvin uses a long copper wire with resistivity 1.68 x 10^-8 Ω⋅m and diameter 1.00 x 10^−3 m to create a solenoid that has a 3

Mazyrski [523]

Answer with Explanation:

We are given that

Resistivity of copper wire= $\rh0=1.68\times 10^{-8}\Omega m$

Diameter=d= $1.00\times 10^{-3} m$

Radius of copper wire= $r=\frac{d}{2}=\frac{1}{2}\times 10^{-3} m$

Radius of solenoid=r' $=3 cm=3\times 10^{-2} m$

1 m=100 cm

a.Length of wire=l=11.3 m

Area of wire=A= $\pi r^2$

Where $\pi=3.14$

A= $3.14\times (\frac{1}{2}\times 10^{-3})^2$

Resistance, R= $\rho \frac{l}{A}$

Using the formula

$R=1.68\times 10^{-8}\times\frac{11.3}{3.14\times (\frac{1}{2}\times 10^{-3})^2}$

$R=0.24\Omega$

B.Length of solenoid= $2\pi r'=2\times 3.14\times 3\times 10^{-2}=0.188$ m

Number of turns= $n_0=\frac{l}{2\pi r'}=\frac{11.3}{0.188}$

$n_0$ =60

C.Potential difference,V=3 V

Current,I= $\frac{V}{R}$

I= $\frac{3}{0.24}=12.5 A$

D.Total length =0.1 m

Number of turns per unit length,n= $\frac{60}{0.1}=600$

Magnetic field along central axis inside of the solenoid,B= $\mu_0 nI$

$B=4\pi\times 10^{-7}\times 12.5\times 600=9.42\times 10^{-3} T$

4 0

3 years ago

Read 2 more answers

Isaiah has samples of two different elements, one metal and one nonmetal

ElenaW [278]

Answer:

1/ As a metal has higher melting point than a nonmetal has, we can guess that sample A is a metal.

2/ The melting point is over 1000 gradius Celcius: 1083 - it's not a low value. And as the sample conducts heat, it is not the element of period N3 in the periodic table, because elements in period 3 do not conduct electricity.

Explanation:

I can not see what the questions 2-3 in your picture is. I answered the question above the table: What can the student conclude about thenidentity of Sample A.

7 0

4 years ago

Two oppositely charged parallel sheets of charge give rise to a field of 9.00×1011 N/C between them. The sheets are square and h

Maksim231197 [3]

Answer:

$Q = 5.75 C$