Answer:
30.22 hours
Explanation:
Given data:
A= l² = (2 x 
)² = 4 x 
m²
Length 'L' = 5m
current '
' = 2 A
density of free electrons 'n'= 8.5 x 
/m³
Current Density 'J' = / A
J= 2/4 x
J= 5 x 
A/m²
We can determine the time required for an electron to travel the length of the wire by
T= L/ Vd
Where,
L is length and Vd is drift velocity.
Vd can be defined by J/ n|q|
where,
n is the charge-carrier number density
|q| is is the charge carried by each charge carrier
=>1.6 x 
C
T= L/ Vd
Therefore,
T= L . n|q| / J
T= (4 x 8.5 x x |1.6 x |)/5 x
T= 108800 seconds =>1813.33 minutes
Converting minute into hours:
T= 30.22 hours
Thus, time that is required for an electron to travel the length of the wire is 30.22 hours
Answer: Paper
Explanation: It is a insulator
Answer:
I would believe that it would be the last option
Explanation:
Physical science is a type of science that mainly focuses on natural objects that are not alive, such as minerals and rocks.
Answer:
The possible quantum numbers for Ca atom when it is in excited
n = 4
l= 1
m =-1,0,1
Explanation:
Given that,
Atomic number = 20
The configuration of Ca
So, The principle quantum number is n =4.
The azimuthal quantum number can take value from 0,1,2...(n-1)
In the ground state, l= 0
When it is excited to p state
Then, l = 1
The magnetic quantum number can take value from l to -l
Hence, The possible quantum numbers for Ca atom when it is in excited
n = 4
l= 1
m =-1,0,1
Answer:
11760J
Explanation:
Given parameters:
Height of hill = 30m
Weight = 40kg
Unknown:
Gravitational potential energy = ?
Solution:
To find the gravitational potential energy, it is the energy due to the position of a body;
G.PE = mgh
m is the mass
g is the acceleration due to gravity
h is the height
Now insert the parameters and solve;
G.PE = 40 x 9.8 x 30 = 11760J
