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tresset_1 [31]
2 years ago
7

The key differences between rotational kinematics and translational kinematics is: A. Rotational kinematics must specify an axis

of rotation and objects return to their initial position with successive revolutions. B. Rotational kinematics must specify an axis of rotation and is only applied to rigid objects, not particles. C. Rotational kinematics analyzes both the tangential acceleration as well as the centripetal acceleration and translational kinematics analyzes only the tangential acceleration. D. Rotational kinematics must specify an axis of rotation and uses only dimensionless units
Physics
1 answer:
inn [45]2 years ago
8 0

In Translational motion, the body moves in a straight line whereas in Rotational motion, the body moves in a circular path.

<h3>Differences between rotational kinematics and translational kinematics</h3>

In Translational motion, the body moves in a straight line and the body same displacement in equal interval of time while on the other hand, in Rotational motion, the body moves in a circular path and the body travels same angular displacement in equal interval of time..

Learn more about motion here: brainly.com/question/453639

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A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When th
aev [14]

Answer:

x_2=1.60m

Explanation:

From the Question We are told that

Initial Force F_1=5800N

Final Force F_2=6500N

Distance between the front and rear wheels \triangle x=3.20 m

Since

 \triangle x=3.20 m

Therefore

 x_1+x_2=3.20

 x_1=3.20-x_2

Generally the equation for The center of mass is at x_2 is mathematically

given by

 x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}

 x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}

 2*F_1*x_2 =3.20F_1

 x_2=1.60m

6 0
2 years ago
Kim took 5 hours to complete a journey with an average speed
monitta

Answer:110

Explanation:

6 0
3 years ago
Definition of Speed?​
ANEK [815]

Explanation:

speed of an object is the magnitude of the rate of change of its position with time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

4 0
2 years ago
Read 2 more answers
A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
2 years ago
Read 2 more answers
What is the radius of a tightly wound solenoid of circular cross-section that has 180turns if a change in its internal magnetic
Nata [24]

Answer:

Radius of cross section, r = 0.24 m

Explanation:

It is given that,

Number of turns, N = 180

Change in magnetic field, \dfrac{dB}{dt}=3\ T/s

Current, I = 6 A

Resistance of the solenoid, R = 17 ohms

We need to find the radius of the solenoid (r). We know that emf is given by :

E=N\dfrac{d\phi}{dt}

E=N\dfrac{d(BA)}{dt}

Since, E = IR

IR=NA\dfrac{dB}{dt}

A=\dfrac{IR}{N.\dfrac{dB}{dt}}

A=\dfrac{6\ A\times 17\ \Omega}{180\times 3\ T/s}

A=0.188\ m^2

or

A=0.19\ m^2

Area of circular cross section is, A=\pi r^2

r=\sqrt{\dfrac{A}{\pi}}

r=\sqrt{\dfrac{0.19}{\pi}}

r = 0.24 m

So, the  radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.

5 0
3 years ago
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