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tresset_1 [31]
2 years ago
7

The key differences between rotational kinematics and translational kinematics is: A. Rotational kinematics must specify an axis

of rotation and objects return to their initial position with successive revolutions. B. Rotational kinematics must specify an axis of rotation and is only applied to rigid objects, not particles. C. Rotational kinematics analyzes both the tangential acceleration as well as the centripetal acceleration and translational kinematics analyzes only the tangential acceleration. D. Rotational kinematics must specify an axis of rotation and uses only dimensionless units
Physics
1 answer:
inn [45]2 years ago
8 0

In Translational motion, the body moves in a straight line whereas in Rotational motion, the body moves in a circular path.

<h3>Differences between rotational kinematics and translational kinematics</h3>

In Translational motion, the body moves in a straight line and the body same displacement in equal interval of time while on the other hand, in Rotational motion, the body moves in a circular path and the body travels same angular displacement in equal interval of time..

Learn more about motion here: brainly.com/question/453639

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Sergio [31]

Answer:

Power = 0.33 Watts

Explanation:

Given the following data;

Distance = 1m

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First of all, we would solve for the work done by the boy.

Workdone = force * distance

Substituting into the equation, we have;

Workdone = 20*1 = 20J

Now to find power;

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8 0
2 years ago
Monochromatic light from a distant source is incident on a slit 0.750 mm wide. On a screen 2.00 m away, the distance from the ce
jasenka [17]

Answer:

\lambda= 506.25 nm

Explanation:

Diffraction is observed when a wave is distorted by an obstacle whose dimensions are comparable to the wavelength. The simplest case corresponds to the Fraunhofer diffraction, in which the obstacle is a long, narrow slit, so we can ignore the effects of extremes.

This is a simple case, in which we can use the Fraunhofer single slit diffraction equation:

y=\frac{m \lambda D}{a}

Where:

y=Displacement\hspace{3}from\hspace{3} the\hspace{3} centerline \hspace{3}for \hspace{3}minimum\hspace{3} intensity =1.35mm\\\lambda=Light\hspace{3} wavelength \\D=Distance\hspace{3}between\hspace{3}the\hspace{3}screen\hspace{3}and\hspace{3}the\hspace{3}slit=2m\\a=width\hspace{3}of\hspace{3}the\hspace{3}slit=0.750mm\\m=Order\hspace{3}number=1

Solving for λ:

\lambda=\frac{y*a}{mD}

Replacing the data provided by the problem:

\lambda=\frac{(1.35\times 10^{-3})*(0.750\times 10^{-3})}{1*2} =5.0625\times 10^{-7}m =506.25nm

7 0
2 years ago
Brainliest if correct
Bad White [126]

Answer:

D: Increase the distance between the objects.

E: Decrease the mass of one of the objects.

6 0
1 year ago
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4 0
2 years ago
Find the wavelength of radio waves of frequency 200kHz
Gala2k [10]
\lambda = \frac{c}{f}
λ - wavelength, c - the speed of light, f - frequency

f=200 \ kHz= 200 000 \ Hz \\ \\&#10;\lambda=\frac{300 000 \ [\frac{km}{s}]}{200 000 \ [Hz]}=\frac{3}{2}=1.5 \ [km]

The wavelength of these waves is 1.5 km.
3 0
2 years ago
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