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Ipatiy [6.2K]
2 years ago
10

Could you please assist me, thank you kindly.

Physics
1 answer:
Bogdan [553]2 years ago
4 0

In Newton's Third law of motion, the 'action' and 'reaction' forces act on different objects.  That's why they don't cancel each other out and always result in zero force.

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An object has an acceleration of 6.0 m/s/s. if the net force acting upon this object were doubled, then its new acceleration wou
Flauer [41]
F has direct relation with a
then doubling F cause acc. to get double i:e 6×2=12
5 0
3 years ago
A block of mass 200g is oscillating on the end of a horizontal spring of spring constant 100 N/m and natural length 12 cm. When
malfutka [58]

In order to determine the acceleration of the block, use the following formula:

F=ma

Moreover, remind that for an object attached to a spring the magnitude of the force acting over a mass is given by:

F=kx

Then, you have:

ma=kx

by solving for a, you obtain:

a=\frac{kx}{m}

In this case, you have:

k: spring constant = 100N/m

m: mass of the block = 200g = 0.2kg

x: distance related to the equilibrium position = 14cm - 12cm = 2cm = 0.02m

Replace the previous values of the parameters into the expression for a:

a=\frac{(\frac{100N}{m})(0.02m)}{0.2\operatorname{kg}}=10\frac{m}{s^2}

Hence, the acceleration of the block is 10 m/s^2

8 0
9 months ago
Why doesn't electric current flow through rubber?
PolarNik [594]
Rubber is a insulator so current cannot pass through it where as metal is a conductor which allows current to pass through it
5 0
2 years ago
Read 2 more answers
HELP PLEASE 20 POINTS SHOW WORK, ALL EQUATIONS
nataly862011 [7]

Answer:

s = 3 m

Explanation:

Let t be the time the accelerating car starts.

Let's assume the vehicles are point masses so that "passing" takes no time.

the position of the constant velocity and accelerating vehicles are

s = vt = 40(t + 2)  cm

s = ½at² = ½(20)(t)² cm

they pass when their distance is the same

½(20)(t)² = 40(t + 2)

10t² = 40t + 80

0 = 10t² - 40t - 80

0 = t² - 4t - 8

t = (4±√(4² - 4(1)(-8))) / 2(1)

t = (4± 6.928) / 2  ignore the negative time as it has not occurred yet.

t = 5.464 s

s = 40(5.464 + 2) = 298.564 cm

300 cm when rounded to the single significant digit of the question numerals.

7 0
3 years ago
In a transformer, energy is carried from the primary coil to the secondary coil by:________
likoan [24]

In a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.

To find the answer, we have to know more about the transformer.

<h3>How transformer works?</h3>
  • An item utilized in the transfer of electric energy is a transformer.
  • AC current is used for transmission.
  • It is frequently used to modify the supply voltage between circuits without altering the AC frequency.
  • The fundamentals of mutual and electromagnetic induction govern how the transformer operates.
  • Magnetic field through the primary coil changes when primary coil current varies. the iron core of the secondary coil likewise has a magnetic field.
  • EMF is therefore generated in the secondary coil.

Thus, we can conclude that, in a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.

Learn more about the transformer here:

brainly.com/question/26787198

#SPJ4

5 0
2 years ago
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