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mezya [45]
4 years ago
12

A cylinder has a length of 3.23 cm, a diameter of 1.75 cm, and a mass of 65.3 grams. What is the density of the cylinder? Based

on its density, of what kind of material might it be made? Material is likely to be: ______________________________ (Show your work.)
Physics
1 answer:
Firlakuza [10]4 years ago
6 0
Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate density as follows:

density = mass / volume
density = 65.3 g / π(1.75/2 cm)^2 ( 3.23 cm )
density = 8.41 g/cm^3
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A net force of magnitude 36N gives an object of mass m1 an acceleration of 6.0m/s2. The same net force gives m1 and another obje
Aneli [31]

In working toward the complete solution of this problem,
I'm going to use addition, subtraction, multiplication, and
division.  Also, I think I'll be using Newtons 2nd law of motion
like at least fifteen times, so I'll write it here for our review: 

                                 Force = (mass) x (acceleration).

-- When 36 N of force acts on m₁ it accelerates at 6 m/s² .

                                             36 N = (m₁) x (6 m/s²)

Divide each side by  6 m/s² :    m₁ = (36 N) / (6 m/s²) = 6 kg . 

-- The same force acting on (m₁+m₂) accelerates them at 2 m/s² .

                                             36 N = (6kg + m₂) x (2 m/s²)

Divide each side by  2 m/s² :    6kg + m₂ = (36N) / (2m/s²) = 18 kg

Subtract  6kg  from each side:            m₂ = 12 kg .

-- The same net force acts on  m₂  alone:

                                             36 N = (12 kg) x (acceleration)

Divide each side by  12 kg :    Acceleration = (36 N) / (12 kg) = 3 m/s² .

8 0
4 years ago
A 6.0 MeV alpha particle beam of cross section 5 cm2 is completely stopped in an ionization chamber producing a saturation curre
Licemer1 [7]

Answer:

v=6.0MeV\\h=6.626\cdot10^{-34}\\dq=33\\

Solution

m_\alpha =6.64\cdot 10^{-27}\\\lambda=\frac{h}{p}\\p=\sqrt{2m\cdot V}\\\lambda=\frac{6.628 \cdot10^{-34}}{\sqrt{2(6.64\cdot10^{-27})(6\cdot10^6)}}\\\\\lambda =2.35\cdot10^{-34}\\Fluence Rate =\frac{d(N)}{d(t)\cdot d(S)}=\frac{d(N)\cdot d(q)}{d(q)\cdot d(t)\cdot d(S)}=\frac{d(N)}{d(q)}\frac{V} {\cdot d(S)}\\\\\=\frac{6\cdot 10^6}{33} \cdot\frac{0.08\cdot10^{-9}}{4\cdot\pi\cdot25\cdot10^{-4}}\\\\=0.000463\\E_p=4.63\cdot10^{-4}\\

=\frac{6*10^6\cdot 0.08*10^{-9}}{33\cdot4\pi\cdot 25*10^-4} \\\\E_P=4.63*10^{-4}

Explanation:

First enlist all the variables

then solve using calculator

6 0
4 years ago
A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (4.0 m
Ilya [14]

Answer:

Work done, W = 3.78 Joules

Explanation:

It is given that,

Displacement in x-y coordinate, d=(4i+5.8j)\ m

Magnitude of force, F = 1.3 N

The force is directed at a counterclockwise angle of 121° from the positive direction of the x axis. Let W is the work done by the force on the coin during the displacement.

Firstly, finding the vector form of force as :

F=1.3\ cos(121)i+1.3\ sin(121)j

F=-0.669i+1.114j

The work done is given by :

W=F.d

W=(-0.669i+1.114j).(4i+5.8j)

W=-0.669\times 4+1.114\times 5.8

W = 3.78 Joules

So, the work done by the force is 3.78 Joules. Hence, this is the required solution.

3 0
3 years ago
A sound wave of wavelength 0.682 m and velocity 325 m/s is produced for 0.500 s. what is the frequency
Naya [18.7K]
Recall that given the velocity and wavelength, frequency can be computed as

frequency =  \frac{speed}{wavelength}
Substituting the given values, we have
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6 0
3 years ago
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madam [21]

Answer:

option D

Explanation:

given,

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angle at which eel rotate

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θ = 28\pi\times \dfrac{1}{120}

θ = 0.733 rad

θ =0.733 \times \dfrac{180^0}{2\pi}

θ =42^0

Hence, the correct answer is option D

4 0
3 years ago
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