In working toward the complete solution of this problem,
I'm going to use addition, subtraction, multiplication, and
division. Also, I think I'll be using Newtons 2nd law of motion
like at least fifteen times, so I'll write it here for our review:
Force = (mass) x (acceleration).
-- When 36 N of force acts on m₁ it accelerates at 6 m/s² .
36 N = (m₁) x (6 m/s²)
Divide each side by 6 m/s² : m₁ = (36 N) / (6 m/s²) = 6 kg .
-- The same force acting on (m₁+m₂) accelerates them at 2 m/s² .
36 N = (6kg + m₂) x (2 m/s²)
Divide each side by 2 m/s² : 6kg + m₂ = (36N) / (2m/s²) = 18 kg
Subtract 6kg from each side: m₂ = 12 kg .
-- The same net force acts on m₂ alone:
36 N = (12 kg) x (acceleration)
Divide each side by 12 kg : Acceleration = (36 N) / (12 kg) = 3 m/s² .
Answer:

Solution


Explanation:
First enlist all the variables
then solve using calculator
Answer:
Work done, W = 3.78 Joules
Explanation:
It is given that,
Displacement in x-y coordinate, 
Magnitude of force, F = 1.3 N
The force is directed at a counterclockwise angle of 121° from the positive direction of the x axis. Let W is the work done by the force on the coin during the displacement.
Firstly, finding the vector form of force as :


The work done is given by :



W = 3.78 Joules
So, the work done by the force is 3.78 Joules. Hence, this is the required solution.
Recall that given the velocity and wavelength, frequency can be computed as

Substituting the given values, we have
Answer: 477 Hz
Answer:
option D
Explanation:
given,
uniform length of cylinder = 1 m
diameter of the cylinder = 10 cm = 0.1 m
Eels have been recorded to spin = 14 rev/s
camera records at = 120 frames per second
time = 
angle at which eel rotate = ?
ω = 14 rev/s
ω = 14 x 2 π rad/s
ω = 28 π rad/s
angle at which eel rotate
θ = ω t
θ = 
θ = 0.733 rad
θ =
θ =
Hence, the correct answer is option D