Car 1: It is an exponential function that is given as P = 18,500 (0.9595)ⁿ and the price after 10 years is $12,235.5.
Car 2: It is a linear function that is given as 2000x + 3y = 55500 and the price after 10 years is $11,833.33.
And Yes, there is a significant difference.
<h3>What is a function?</h3>
A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.
Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.
Car 1 (value in dollars)
Year 1: 18,500
Year 2: 17,390
Year 3: 16,346.60
Car 2 (value in dollars)
Year 1: 18,500
Year 2: 17,500
Year 3: 16,500
The exponential function describes car 1.
Then the function will be
![\rm P = 18500\times (0.95995)^n](https://tex.z-dn.net/?f=%5Crm%20P%20%3D%2018500%5Ctimes%20%280.95995%29%5En)
The linear function describes car 2.
![\rm y \ - \ 18500 = \dfrac{-2000}{3}(x - 0)\\\\\\3y - 55500 = -2000x\\\\\\2000x +3y = 55500](https://tex.z-dn.net/?f=%5Crm%20y%20%5C%20-%20%5C%2018500%20%3D%20%5Cdfrac%7B-2000%7D%7B3%7D%28x%20-%200%29%5C%5C%5C%5C%5C%5C3y%20-%2055500%20%3D%20-2000x%5C%5C%5C%5C%5C%5C2000x%20%2B3y%20%3D%2055500)
Then the value of the car 1 after 10 years will be
![\rm P = 18500\times (0.95995)^{10}\\\\\\P = \$ \ 12,235.5](https://tex.z-dn.net/?f=%5Crm%20P%20%3D%2018500%5Ctimes%20%280.95995%29%5E%7B10%7D%5C%5C%5C%5C%5C%5CP%20%3D%20%5C%24%20%5C%2012%2C235.5)
Then the value of the car 2 after 10 years will be
![\rm 2000 \times 10 +3y = 55500\\\\y = \$ \ 11,833.33](https://tex.z-dn.net/?f=%5Crm%202000%20%5Ctimes%2010%20%2B3y%20%3D%2055500%5C%5C%5C%5Cy%20%3D%20%20%5C%24%20%5C%2011%2C833.33)
Yes, there is a significant difference.
More about the function link is given below.
brainly.com/question/5245372
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