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Assoli18 [71]
3 years ago
7

A chemist weighed out 70.8 g of magnesium. Calculate the number of moles of magnesium she weighed out. Round your answer to sign

ificant digits.

Chemistry
2 answers:
solniwko [45]3 years ago
8 0

Answer:

2.91 grams of Magnesium

Explanation:

I put a picture . I used the molar mass of magnesium which can be calculated from the periodic table or simply google it. :) I hope it helps - Enrique

AlekseyPX3 years ago
4 0
You first take the weighed out amount of magnesium then you divide by the actual mass of magnesium 24.305 g. 70.8/24.305 = 2.912980868134129. Then you multiply by Avagadros number 6.02x10^23. 2.9129 x 6.02x10^23 = 1.753614482617^24. Then round it to 1.75^24 moles of magnesium
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Answer:

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Explanation:

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Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

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V_1 = initial volume of gas = 27.5 mL

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T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

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