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Korolek [52]
3 years ago
12

Twice the sum of a number is 9 is equal to three times the difference of the number and 7

Mathematics
2 answers:
docker41 [41]3 years ago
5 0

"Twice the sum of a number is 9 is equal to three times the difference of the number and 7" is our problem. Let's translate it into an equation.

Twice                                      2 times

the sum of a number           x +

and 9                                    9

is equal to                              =

three times                           3 times

the difference of a number x-

and 7                                      7


We move top down on the right side and make the equation. Then we solve it for x

2x + 9 = 3x - 7                           our equation

-x + 9 = -7                                    subtract 3x on both sides

-x = -16                                      subtract 16 on both sides

x = 16                                         divide both sides by -1


Thus the mystery number is 16.

soldi70 [24.7K]3 years ago
3 0
First, write put the information into an equation

2*(x+9) = 3*(x-7)

distribute the 2 and 3
2x + 18 = 3x - 21

Combine like terms (Xs and munbers) (in this case, it's easier to add 15 to both sides and subtract 2x from both sides so both sides end up being positive)
33 = x

x=33
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tankabanditka [31]

Answer:

Given

x+y+z=0

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⟹x 3 +y 3 +3xy(x+y)=−z 3

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Step-by-step explanation:

Hope it is helpful.....

8 0
2 years ago
If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.
Pie
Given that f^{(n)}(0)=(n+1)!, we have for f(x) the Taylor series expansion about 0 as

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n

Replace n+1 with n, so that the series is equivalent to

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}

and notice that

\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}

Recall that for |x|, we have

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

which means

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}
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3 years ago
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sergiy2304 [10]

Answer:

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What fraction plus another fraction = -7/36
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Answer:

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Step-by-step explanation:

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3 years ago
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