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Ray Of Light [21]
3 years ago
12

Factor using special products 9/16 a2−2ab+ 16/9 b2

Mathematics
1 answer:
almond37 [142]3 years ago
5 0

Answer:

<em>Answer</em><em> </em><em>is</em><em> </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

Given \: question \: is \\  \frac{9}{16}  {a}^{2}  - 2ab +  \frac{16}{9  }  {b}^{2}  \\  { (\frac{3}{4}a) }^{2}  - 2ab +   {( \frac{4}{3}b )}^{2}  \\  \\      (\frac{3}{4} a +  \frac{4}{3} b)^2 \\

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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3 years ago
Suppose that replacement times for washing machines are normally distributed with a mean of 9.4 years and a standard deviation o
Nezavi [6.7K]

Using the normal distribution, it is found that the replacement time that separates the top 18% from the bottom 82% is of 11.23 years.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are, respectively, given by \mu = 9.4, \sigma = 2.

The desired value is the 82nd percentile, which is X when Z = 0.915, hence:

Z = \frac{X - \mu}{\sigma}

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X = 11.23

The replacement time that separates the top 18% from the bottom 82% is of 11.23 years.

More can be learned about the normal distribution at brainly.com/question/24663213

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