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Elenna [48]
3 years ago
10

Sophia exchanged 1,000 US dollars for the south African currency. the exchange rate was 7.15 rand to $1.00.

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0
1 / 7.15 = 1000 / x......$ 1 to 7.15 rand = $ 1000 to x rand
cross multiply because this is a proportion
(1)(x) = (7.15)(1000)
x = 7150 <=== Sophia got 7150 rand
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Which value of m will create a system of parallel lines with no solution? y=mx-6 8x-4y=12 A coordinate grid with one line labele
nydimaria [60]

Answer:

A system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2

Step-by-step explanation:

The equation of the given line is 8·x - 4·y = 12

Which gives;

8·x- 12= 4·y

y = 2·x - 3

Given that the line passes through the points (0, -3) and (1, -1), we have;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

When (x₁, y₁) = (0. -3) and (x₂, y₂) = (1, -1), we have;

Slope, \, m =\dfrac{(-1)-(-3)}{1-(0)} = 2

y - (-3) = 2×(x - 0)

y = 2·x - 3 which is the equation of the given line

For the lines 8·x - 4·y = 12, which is the sane as y = 2·x - 3 and the line y = m·x  - 6 to have no solution, the slope of the two lines should be equal that is m = 2

Given that the line passes through the point (1.5, 0), we have;

y - 0 = 2×(x - 1.5)  

y = 2·x - 3...................(1)

For the equation, y = m·x  - 6, when m = 2, we have;

y = 2·x  - 6..................(2)

Solving equations (1) and (2) gives;

2·x - 3 = 2·x  - 6, which gives;

2·x - 2·x=  - 3 - 6

0 = 9

Therefore, a system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2.

4 0
3 years ago
Ken's landscape gardening business creates odd-shaped lawns that include semicircles. Find the area of this semicircular section
salantis [7]

Answer:

Area of semicircular lawn is 9.82 square meter.

Step-by-step explanation:

Given:

Diameter of the semicircle = 5 m

So we will find the radius.

Radius is half of the diameter.

Radius r=\frac{5}{2}=2.5\ m

We need to find the area of the lawn.

Solution:

Now we know that;

Area of semicircle is half times π times square of the radius.

framing in equation form we get;

Area of semicircular lawn = \frac12\pi r^2=\frac12\times\frac{22}{7}\times 2.5\times 2.5=9.82\ m^2

Hence Area of semicircular lawn is 9.82 square meter.

7 0
3 years ago
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