First calculate the hourly rate, which is the difference of cleaning 2 and 1 rooms:
175-125=50
then calculate the initial value by subtracting the hourly rate from the "1 room" cost:
125-50=75
The initial cost might be something like driving to the place (which is only necessary once), while the rate covers work time or cleaning utensils used.
Answer:
Step-by-step explanation:
Answer:
a) 99.97%
b) 65%
Step-by-step explanation:
• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.
• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.
• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.
Mean of 98.35°F and a standard deviation of 0.64°F.
a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the mean, or between 96.43°F and 100.27°F?
μ - 3σ
98.35 - 3(0.64)
= 96.43°F
μ + 3σ.
98.35 + 3(0.64)
= 100.27°F
The approximate percentage of healthy adults with body temperatures is 99.97%
b. What is the approximate percentage of healthy adults with body temperatures between 97 .71°F and 98.99°F?
within 1 standard deviation from the mean - that means between μ - σ and μ + σ.
μ - σ
98.35 - (0.64)
= 97.71°F
μ + σ.
98.35 + (0.64)
= 98.99°F
Therefore, the approximate percentage of healthy adults with body temperatures between 97.71°F and 98.99°F is 65%
I can’t see the scenario on top so can’t rlly help u out sorry
60 more students voted for Kevin
Step-by-step explanation:
Given
total students = 300
Voted for Jennifer = 40%
Voted for Kevin = 60%
We will find number of students for one of them and then will subtract from total to find the others.
So,
Students who voted for Jennifer:

Students who voted for Kevin
=
In order to calculate that how many more students voted for Kevin :
180-120 = 60
Hence,
60 more students voted for Kevin
Keywords: Percentage
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