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ryzh [129]
3 years ago
6

You throw a baseball a distance of 20 meters. Is it work or not work?

Physics
1 answer:
OverLord2011 [107]3 years ago
7 0
Yes it is work because when you throw a ball, you transfer energy to it and it moves.
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What inflammatory molecule aids with muscle building and is released when muscles experience microscopic damage?
Reika [66]

Answer:

Cytokines

Explanation:

Cytokines are known as inflammatory molecules which are also proteinous and aid signaling of certain processes and conditions in the body.

They are also normally involved in aiding muscle building and are released when muscles experience microscopic damage which may lead to the muscles being sore.

3 0
3 years ago
A skateboarder who travels 60 meters in 30 seconds has a speed of
natulia [17]

2m/s

Explanation:

Given parameters:

Distance traveled = 60m

time taken = 30seconds

Unknown:

Speed of skateboarder = ?

Solution:

Speed is the rate of change of distance with time taken. It is a scalar quantity that only revers magnitude;

    Speed = \frac{distance}{time}

    Speed = \frac{60}{30} = 2m/s

learn more:

Speed brainly.com/question/1548911

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4 0
3 years ago
Which of the following statements is true about tides? (2 points)
andre [41]
1: <span>Tides are caused by the location of the Earth, sun, and moon.

2: </span><span>Tides occur about an hour later each day.
This is because of the earth's orbit and the moons position as they move.
</span><span>
3: </span>Half as much as the moon
The moon affects the tide much more than the sun, as the moon is drastically closer to the earth than the sun.
4 0
4 years ago
Read the paragraph below from the section "An Object At Rest Has Potential Energy
ch4aika [34]
I think it’s d because it talks about a spring with is common like the spring in a pen
8 0
4 years ago
g calculate the effectiveness radiation dosage in sieverts for a 79 kg person who is exposed 6.8x10^9
Elza [17]

Answer:

The answer is "\bold{dosage = 0.031 rem}"

Explanation:

please find the complete question in the attached file.

Given value:

m = 79\  kg  \\\\n = 3.4 \times  10^9 \\\\E = 5.5  \times  10^{-13} \\\\ RBE = 15

\to E = n E\\

        = 3.4  \times  10^9  \times  5.5  \times  10^{-13} \\\\      = 1.87 \times  10^{-3}

\to E(absorbed) = 1.87  \times 10^{-3}  \times  0.87 = 1.63  \times  10^{-3}

calculating the radiation absorbed per kg:

= \frac{1.63  \times  10^{-3}}{79}  \\\\ = 2.06  \times  10^{-5} \\\\ = 0.00206 \  rad

\to Dosage = 0.00206  \times  15 \\

                 = 0.031 \ \ rem

4 0
3 years ago
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