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3 years ago

Calculate the heat energy conducted per hour through the side walls of a cylindrical steel

Physics

1 answer:

Maru [420]3 years ago

7 0

Explanation:

heat caoacity and heat is difference

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if you drop a stone from height of 2.5m. what is the speed of the stone right before it hits the ground?

KonstantinChe [14]

Since the stone was dropped from height, its initial velocity = 0 m/s

Using v² = u² + 2gs.

Where g ≈ 10 m/s², u = initial velocity = 0 m/s, s = height from drop = 2.5 m

v² = u² + 2gs

v² = 0² + 2*10*2.5

v² = 0 + 50

v² = 50

v = √50

v ≈ 7.07 m/s

Hence velocity just before hitting the ground is ≈ 7.07 m/s

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3 years ago

Which ramp requires the least amount of force?

irinina [24]

Length 4ft height 1ft

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3 years ago

A 6V radio with a current of 2A is turned on for 5 minutes. Calculate the energy transferred in joules

iogann1982 [59]

Answer:

R=V/I=6/2=3ohm

time =5minutes =5*60=300seconds

I=2A

Heat =I^2Rt=(2)^2*3*300=4*900=3600J

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3 years ago

The elements are mostly likely to form more than one type of ion are the

Ghella [55]

Alkali Metals ......................................

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3 years ago

You have two solid blocks of metal wrapped in paper. The blocks are the same size, but one is pure aluminum and the other is pur

puteri [66]

Answer:

We can identify easily which block has more density, if we try to lift each one, and the heavier will be the one with more density. In this case the block of iron will be the one with more density.

Explanation:

To understand this we will give some numerical values to give the best explanation of this situation.

Let's say that we have the two blocks over one table, and over the table there is a special scale to measure the mass of an object.

Both block have the same dimensions, and seaching information of density by internet we find that the density for the iron is 7850 [kg/m^3], and the density for the aluminum is 2712 [kg/m^3]

Now the dimension of each bloack are 10*10*10 [cm] so, the volume will be 1000 [cm^3] = 0.001[m^3]

Now using the expression of density:

$density = \frac{m}{v} \\where:\\m = mass [kg]\\v= volume [m^{3} ]\\m = density* volume$

for the iron

$miron=7850*0.001 = 7.85 [kg]\\$

for the aluminum

$malumi=2712*0.001=2.712[kg]$

Therefore the weight of the iron will be always almost 3 times heavier than the weight of the aluminum.

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3 years ago