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4 years ago

The force of gravity between two objects is directly proportional to which of the following?

2 answers:

8 0

Force of gravity =Gxm1xm2 /r^2 G= gravitational constant m1 and m2 are masses r is the distance between masses. So a is the correct option

Levart [38]4 years ago

5 0

<span>The force of gravity between two objects is directly proportional to the
product of the two masses, and to the mass of each object individually. </span>

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A body of density 9.0cm appears to have mass 27.0g in a liquid of density 1.2gcm. What is the volume of the solid?

Alika [10]

Answer:

v * 9.0 = 27.0 + (v * 1.2)

7 0

3 years ago

Observe: Air pressure is equal to the weight of a column of air on a particular location. Air pressure is measured in hectopasca

babymother [125]

Answer:

A. When moving towards a high pressure center the pressure values increase in the equipment

B. This area is called high prison since the weight of the atmosphere on top is maximum

Explanation:

A) A high atmospheric pressure system is an area where the pressure is increasing the maximum value is close to 107 Kpa, the other side as low pressure can have small values 85.5 kPa.

When moving towards a high pressure center the pressure values increase in the equipment

B) This area is called high prison since the weight of the atmosphere on top is maximum

in general they are areas of good weather

4 0

3 years ago

In principle, when you fire a rifle, the recoil should push you backward. How big a push will it give? Let’s find out by doing a

mixer [17]

Answer:

0.07142 m/s in the opposite direction of the bullet

Explanation:

$m_1$ = Mass of rifle = 70 kg

$m_2$ = Mass of bullet = 0.01 kg

$v_1$ = Velocity of rifle

$v_2$ = Velocity of bullet = 500 m/s

As the momentum of the system is conserved

$m_1v_1+m_2v_2=0\\\Rightarrow v_1=-\frac{m_2v_2}{m_1}\\\Rightarrow v_1=-\frac{0.01\times 500}{70}\\\Rightarrow v_1=-0.07142\ m/s$

The recoil velocity of the rifle is -0.07142 m/s

The negative sign shows the opposite direction of the rifle.

3 0

3 years ago

From the window of a building, a ball is tossed from a height y0 above the ground with an initial velocity of 8.10 m/s and angle

GarryVolchara [31]

Answer:

Part a)

$y = 88.5 m$

Part b)

$v_x = 7.7 m/s$

$v_y = 2.5 m/s$

Part c)

equation of position in x direction is given as

$x = v_x t$

equation of position in y direction is given as

$y = v_y t + \frac{1}{2}gt^2$

Part d)

$x = 30.8 m$

Part e)

H = 88.5 m

Part f)

t = 1.2 s

Explanation:

As we know that ball is projected with speed

v = 8.10 m/s at an angle 18 degree below the horizontal

so we will have

$v_x = 8.10 cos18$

$v_x = 7.7 m/s$

$v_y = 8.10 sin18$

$v_y = 2.5 m/s$

Part a)

Since it took t =4 s to reach the ground

so its initial y coordinate is given as

$y = v_y t + \frac{1}{2}a_y t^2$

$y = 2.5(4) + \frac{1}{2}(9.81)(4^2)$

$y = 88.5 m$

Part b)

components of the velocity is given as

$v_x = 8.10 cos18$

$v_x = 7.7 m/s$

$v_y = 8.10 sin18$

$v_y = 2.5 m/s$

Part c)

equation of position in x direction is given as

$x = v_x t$

equation of position in y direction is given as

$y = v_y t + \frac{1}{2}gt^2$

Part d)

distance where it will strike the floor is given as

$x = v_x t$

$x = 7.7 \times 4$

$x = 30.8 m$

Part e)

Height from which it is thrown is same as initial y coordinate of the ball

so it is given as

H = 88.5 m

Part f)

time taken by ball to reach 10 m below is given as

$y = v_y t + \frac{1}{2}gt^2$

$10 = 2.5t + \frac{1}{2}(9.81) t^2$

t = 1.2 s

7 0

3 years ago

Match each chemical name with the correct chemical formula.

pochemuha

Is there any chemical names listed ?

4 0

3 years ago