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mrs_skeptik [129]
3 years ago
14

2+17+8 rewritten correctly using the commutative property and then simplified correctly

Mathematics
2 answers:
zheka24 [161]3 years ago
7 0

Answer:

Step-by-step explanation:

I am sorry this is to confusing for me

miv72 [106K]3 years ago
7 0

Answer:

27.

Step-by-step explanation:

I am assuming 'correctly' means in ascending order.

Using the commutative property of addition:

2 + 17 + 8

= 2 + 8 + 17

= 10 + 17

= 27.

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20 pen cost $1.60 what is the unit rate
Blababa [14]

1.60/20 =0.08

0.08 per pen
3 0
3 years ago
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Is the product of fifteen negative integers positive or negative?
enot [183]

Answer:

the sign of the product of 15 negative numbers will be negative

Step-by-step explanation:

Heya mate!!

The product of odd numbers is odd and the product of even numbers is even.

so 15 is an odd number then the sign of product is odd

Hope this helps!!!

3 0
3 years ago
What is the value of f(x)=2•2^x for f(-2)
Zigmanuir [339]

Answer:

The value of f(-2) is 1/2 or it can be written as 0.5.

Step-by-step explanation:

The given function is

f(x)=2\cdot 2^x

We have to find the value of f(-2).

Substitute x=-2 in the given function to find the value of f(-2).

f(-2)=2\cdot 2^(-2)

f(-2)=2\cdot \frac{1}{2^(2)}

f(-2)=\frac{1}{2}

f(-2)=0.5

Therefore the value of f(-2) is 1/2 or it can be written as 0.5.

3 0
3 years ago
Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a^2 – 18 square units. Which i
netineya [11]

we know that

The area of the hexagon is equal to the sum of the areas of the six equilateral triangles

Let

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so

6x=24a^{2} -18

Divide by 6 both sides

x=4a^{2} -3 -------> area of one equilateral triangle

To find an equivalent expression for the area of the hexagon based on the area of a triangle, multiply the area of one equilateral triangle by 6

6*(4a^{2} -3)

therefore

the answer is

The equivalent expression is equal to 6*(4a^{2} -3)

6 0
3 years ago
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If a particular set of data is approximately normally distributed, we would find that approximately A) 2 of every 3 observations
Kryger [21]

Answer:

A) No

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C) Yes

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2/3  = 0.67    or  67 %

We know tha the interval

[μ  -  σ/2 ,  μ + σ/2]  is approximately 68.3 % of the values

Therefore 2 out of 3 would not fall in that interval

B)

4 out of  5   is  4/5    = 0,8     or 80 %  If we  examine the interval

[μ  -  σ ,  μ + σ ]   which is approximately 95. Then value 4/5  ( 0,8)

Therefore 0,8 is out of the interval

C) 19/20 = 0,95     or 95 % is almost exact the value for the interval

[μ  -  1.5σ ,  μ + 1.5σ ]  That value is inside  μ - 2σ , μ + 2

8 0
3 years ago
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