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3 years ago

One reason people around the world use coal as an energy source is

Chemistry

2 answers:

BlackZzzverrR [31]3 years ago

6 0

Because, it can be found in many areas/places. I hope this helps!

kiruha [24]3 years ago

4 0

It is an energy source that the world has an abundance in.

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Find the percentage composition of a compound that contains 1.94 g of carbon, 0.48 g of hydrogen, and 2.58 g of sulfur.

Svetradugi [14.3K]

Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

Explanation :

To calculate the percentage composition of element in sample, we use the equation:

$\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100$

Given:

Mass of carbon = 1.94 g

Mass of hydrogen = 0.48 g

Mass of sulfur = 2.58 g

First we have to calculate the mass of sample.

Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur

Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g

Now we have to calculate the percentage composition of a compound.

$\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%$

$\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%$

$\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%$

Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

3 0

3 years ago

Why do scientists classify organisms?

Fittoniya [83]

Answer:

Explanation:

Please give brainliest

6 0

3 years ago

For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a cl

Usimov [2.4K]

Answer: The approximate equilibrium partial pressure of $H_2S$ is 3.92 atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

$K_p=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

$1.5\times 10^{-5}=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

On reversing the reaction:

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

initial pressure 4.00atm 2.00 atm 0

eqm (4.00-2x)atm (2.00-x) atm 2x atm

$K_p=\frac{[H_2S]^2}{[H_2]^2\times [S_2]}$

$K_p'=\frac{1}{K_p}=0.67\times 10^5$

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

$0.67\times 10^5=\frac{2x]^2}{[4.00-2x]^2\times [2.00-x]}$

$x=1.96$

$[H_2S]=2x=2\times 1.96=3.92 atm$

Thus approximate equilibrium partial pressure of $H_2S$ is 3.92 atm

3 0

3 years ago

Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Lo

Fiesta28 [93]

The complete question is: Match the following; Disulfide BondsA. Covalent interactions not found in all proteins.Peptide BondsB. Covalent interactions found in all proteins.Long-range interactionsC. Non-covalent interaction formed primarily on the interior of water-soluble proteins.Hydrophobic coreD. Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.

The answer

Disulfide Bonds (Covalent interactions not found in all proteins.)

Peptide Bonds (Covalent interactions found in all proteins.)

Long-range interactions (Covalent or non-covalent interactions formed b/w amino acid far from each other in primary structure.)

Hydrophobic core. (Non-covalent interaction formed primarily on the interior of water-soluble proteins.)

Explanation:

The phrases have been given the right meaning enclosed in a parentheses. The should be matched accordingly as presented.

5 0

3 years ago

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Calculate pH value in a solution that has a<br> concentration of 0.04 mol / dm^3 of H30+ ions?

Sergio039 [100]

Answer:288229262427020202625369201010910000000000000

Explanation: bcuz I said

4 0

3 years ago