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ycow [4]
3 years ago
14

NaOH + HCl → NaCl + H2O

Chemistry
1 answer:
bearhunter [10]3 years ago
7 0

Answer:

0.00496 g H2O

Explanation:

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Which atom or ion is the largest?<br><br> A. K<br> B. K+<br> C. Ca<br> D. Ca2+<br> E. Li
pishuonlain [190]

Answer:

A. K

Step-by-step explanation:

Remember the trends in the Periodic Table:

  • Atomic radii <em>decrease</em> from left to right across a Period.
  • Atomic radii <em>increase</em> from top to bottom in a Group.
  • Ionic radii of metal cations are <em>smaller</em> than those of their atoms.

Thus, the largest atoms are in the lower left corner of the Periodic Table.

The diagram below shows that K is closest to the lower left, so it is the largest atom. It is also larger than any of the cations.

5 0
3 years ago
What does n, l and s mean in chemistry?
kirill [66]

Answer:

These three numbers, n, ℓ, and s can be used to describe an electron in a stable atom.

Explanation:

Each electron's quantum numbers are unique and cannot be shared by another electron in that atom. This property is called the Pauli Exclusion Principle.

Hope this helps!!! :)))

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6 0
3 years ago
What is the section of lithosphere that carries crust
Tanya [424]
The best answer that I can give you is, the Plate.
6 0
3 years ago
According to the balanced equation shown below, 1.00 mole of oxalic acid, h2c2o4, reacts with _________ moles of permanganate io
zheka24 [161]
The balanced equation that shows the reaction between oxalic acid and permanganate ion in an acidic medium is: 2MnO4- + 5H2C2O4 + 6H+ -> 2Mn(2+) + 10CO2 + 8H2O. Thus, 1 mole of oxalic acid reacts with 0.4 mole of permanganate ion. This was obtained using stoichiometry:

1 mol H2C2O4 x (2 mol MnO4-/ 5 mol H2C2O4) = 0.4 mol MnO4- 

In this redox reaction, the permanganate is reduced to manganese(II) ion.
6 0
3 years ago
Calculate the DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide. DH°f means delta or change
USPshnik [31]

Answer: +178.3 kJ

Explanation:

The chemical equation  follows:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(CaO(s))})+(1\times \Delta H^0f_{CO_2}]-[(1\times \Delta H^o_f_{(CaCO_3(s))})]

We are given:

\Delta H^o_f_{(CaO(s))}=-635.1kJ/mol\\\Delta H^o_f_{(CaCO_3(s))}=-1206.9kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-635.1))+(1\times (-393.5))]-[(1\times (-1206.9))]

The DH°rxn for the decomposition of calcium carbonate to calcium oxide and carbon dioxide is +178.3 kJ

5 0
3 years ago
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