All categories

3 years ago

When a 1.0 M solution of HCl is titrated with a 1.0 M solution of KOH, which is the approximate pH at the equivalent point?

1 answer:

4 0

The equivalence point is when the concentration of H⁺ in solution is equal to the concentration of OH⁻ in solution. Since H⁺ and OH⁻ react with each other to make water (H⁺(aq)+OH⁻(aq)→H₂O(l)) the pH at the equivalence point is 7 due to everything being neutralized. (The equivalence point only has a pH of 7 when a strong acid is being titrated with a strong base).

I hope this helps. Let me know if anything is unclear.

You might be interested in

Carvone is a substance that occurs in two forms having different arrangements of the atoms but the same molecular formula (c10h1

Korvikt [17]

The molecular mass of Carvone is calculated as;

= 12 (C)₁₀ + 1.008 (H)₁₄ + 16 (O)

= 120 + 14.112 + 16

= 150.112

%age of Carbon;

= (120 ÷ 150.112) × 100

= 79.94 %

%age of Hydrogen;

= (14.112 ÷ 150.112) × 100

= 9.40 %

%age of Oxygen;

= (16 ÷ 150.112) × 100

= 10.65 %

7 0

3 years ago

Bromine has two isotopes 79Br and 81Br, whose masses (78.9183 and 80.9163 amu) and abundances (50.69% and 49.31%, respectively)

Reika [66]

Answer:

Average atomic mass = 79.9034 amu

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

For first isotope:

% = 50.69 %

Mass = 78.9183 amu

For second isotope:

% = 49.31 %

Mass = 80.9163 amu

Thus,

$Average\ atomic\ mass=\frac{50.69}{100}\times {78.9183}+\frac{49.31}{100}\times {80.9163}\ amu$

$Average\ atomic\ mass=40.0036+39.8998\ amu$

Average atomic mass = 79.9034 amu

4 0

3 years ago

How many moles does the mass quantity 130g of H2O have?

SVETLANKA909090 [29]

It has 7.22 moles.... mole =mass/molar mass
molar mass of H2O=18
130/18=mole

7 0

3 years ago

"a reaction was performed in which 0.57 g of 2-naphthol was reacted with a slight excess of 1-bromobutane to make 0.32 g of 2-bu

murzikaleks [220]

Convert 0.47g 2-naphthol to mols. mol = g/molar mass.
Using the coefficients in the balanced equation, convert mols 2-naphthol to mols 2-butoxynaphthalene then you have to Convert mol 2-butoxynaphthalene to grams. g = mols x molar mass. This is the theoretical yield.

8 0

3 years ago

A substance undergoes a change. Which of the following indicates that the change

LekaFEV [45]

Answer:

change of color

Explanation:

when a substance undergoes a change of color it is an indication that it was chemical

5 0

3 years ago