Answer:
I = PRT
18 = 150(R)(2)
18 = 300R
R = 0.06
So A is correct.
Let me know if this helps!
Answer:
14.4 m/s²
Explanation:
The acceleration is the variation of speed divided by the time:
72/5 = 14.4 m/s²
It has no effect whatsoever.
The Earth, the moon, the ISS, and every TV satellite, all take exactly the same number of days to circle the Sun.
Answer:
Frequency, f = 0.38 Hz
Explanation:
Time period of the spring, T = 2.6 seconds
We need to find the frequency of oscillation for a mass on the end of spring. The relation between the time period and the frequency is given by :
Let f is the frequency of oscillation. So,

f = 0.38 Hz
or
f = 0.4 Hz
So, the frequency of oscillation for a mass on the end of a spring is 0.38 hertz. Hence, this is the required solution.
Answer:
The first one (60%)
Explanation:
The first one converts 15% more energy than the other one. Therefore, it is more efficient.
Hope this helps!