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Setler [38]
3 years ago
7

Northrop aircraft developed and built a deceleration sled to test the effects of the extreme forces on humans and equipment. In

this sled a test pilot with the mss of 70 kg undergoes a sudden negative acceleration of 490 m/s. This deceleration occurs over a distance of 8.05 m. How much work is done against the pilots body during the deceleration?
Physics
1 answer:
dolphi86 [110]3 years ago
4 0
20 hours i think that what they do
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How many molecules of Oxygen gas are there on the reactant side of this equation?
Sergeeva-Olga [200]

Answer:

4

Explanation:

It has 8 O atoms and 4 O2(g) molecules

8 0
2 years ago
A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th
xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}

(b) The tension, T, is given by

v =\sqrt{\dfrac{T}{\mu}}

where v is the speed, T is the tension and \mu is the mass per unit length.

Hence,

T = \mu\cdot v^{2}

To determine \mu, we need to know the mass of the cable. We use the density formula:

\rho = \dfrac{m}{V}

where m is the mass and V is the volume.

m=\rho\cdot V

If the length is denoted by l, then

\mu = \dfrac{m}{l} = \dfrac{\rho\cdot V}{l}

T = \dfrac{\rho\cdot V}{l} v^{2}

The density of steel = 8050 kg/m3

The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is

V = \pi \dfrac{d^{2}}{4} l

T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2

T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

T = 11159.4186\ldots \text{ N} = 11000 \text{ N}

4 0
3 years ago
What is the inverse of f ( x ) ? <br><br>f ( x ) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7Bx%20-%206%7D" id="TexFormu
vladimir1956 [14]

The inverse of f(x) is (6x + 2)/x.

<h3>What is an inverse function?</h3>

The inverse function is defined as a function obtained by reversing the given function.

Given that f(x) = 2/(x-6)

To determine the inverse of a function, all you have to do is switch where x and y are and resolve for y.

So after switching x and y,

f(x) = y = 2/(x-6)

becomes

x = 2/(y - 6)

Now, we solve for y regularly.

f(x) = y = 2/(x-6)

Solve for y :

⇒ x(y - 6)  =2

⇒ xy - 6x = 2

⇒ y = (6x + 2)/x

Therefore the inverse of f(x) is (6x + 2)/x

Learn more about inverse function here:

brainly.com/question/2541698

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5 0
1 year ago
Write at least on paragraph about space exploration and why it interests you.
saw5 [17]

Answer:

use Myassignmenthelp.com it's free

6 0
2 years ago
A spherical steel ball bearing has a diameter of 2.540 cm at 20.00°C. (Assume the coefficient of linear expansion for steel is 1
shusha [124]

Answer:

(a) 2.542 cm

(b) 272.7°C

Explanation:

diameter, d = 2.540 cm

T1 = 20°C

α = 11 x 10^-6 /°C

(a) Let d' be the diameter.

T2 = 87°C

Use he formula for the areal expansion

A' = A ( 1 + βΔT)

where, β is the coefficient of areal expansion and ΔT is teh rise in temperature, A' be the area at high temperature and A be the area at low temperature.

β = 2 α = 2 x 11 x 106-6 = 22 x 10^-6 /°C

So,

\frac{\pi D'^{2}}{4}=\frac{\pi D^{2}}{4}\left ( 1+\beta \Delta T \right )

D'^2 = 2.54^2 ( 1 + 22 x 10^-6 x 67)

D' = 2.542 cm

(b) Let the change in temperature is ΔT.

Use the formula for the volumetric expansion

ΔV = V x γ x ΔT

Where, γ = 3 x α = 3 x 11 x 10^-6 = 33 x 10^-6 /°C

0.9/100 = 33 x 10^-6 x ΔT

ΔT = 272.7°C

6 0
3 years ago
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