Answer:
4
Explanation:
It has 8 O atoms and 4 O2(g) molecules
Answer:
(a) 89 m/s
(b) 11000 N
Explanation:
Note that answers are given to 2 significant figures which is what we have in the values in the question.
(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

(b) The tension,
, is given by

where
is the speed,
is the tension and
is the mass per unit length.
Hence,

To determine
, we need to know the mass of the cable. We use the density formula:

where
is the mass and
is the volume.

If the length is denoted by
, then


The density of steel = 8050 kg/m3
The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is




The inverse of f(x) is (6x + 2)/x.
<h3>What is an inverse function?</h3>
The inverse function is defined as a function obtained by reversing the given function.
Given that f(x) = 2/(x-6)
To determine the inverse of a function, all you have to do is switch where x and y are and resolve for y.
So after switching x and y,
f(x) = y = 2/(x-6)
becomes
x = 2/(y - 6)
Now, we solve for y regularly.
f(x) = y = 2/(x-6)
Solve for y :
⇒ x(y - 6) =2
⇒ xy - 6x = 2
⇒ y = (6x + 2)/x
Therefore the inverse of f(x) is (6x + 2)/x
Learn more about inverse function here:
brainly.com/question/2541698
#SPJ1
Answer:
use Myassignmenthelp.com it's free
Answer:
(a) 2.542 cm
(b) 272.7°C
Explanation:
diameter, d = 2.540 cm
T1 = 20°C
α = 11 x 10^-6 /°C
(a) Let d' be the diameter.
T2 = 87°C
Use he formula for the areal expansion
A' = A ( 1 + βΔT)
where, β is the coefficient of areal expansion and ΔT is teh rise in temperature, A' be the area at high temperature and A be the area at low temperature.
β = 2 α = 2 x 11 x 106-6 = 22 x 10^-6 /°C
So,

D'^2 = 2.54^2 ( 1 + 22 x 10^-6 x 67)
D' = 2.542 cm
(b) Let the change in temperature is ΔT.
Use the formula for the volumetric expansion
ΔV = V x γ x ΔT
Where, γ = 3 x α = 3 x 11 x 10^-6 = 33 x 10^-6 /°C
0.9/100 = 33 x 10^-6 x ΔT
ΔT = 272.7°C