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3 years ago

15

I have 2 bulbs one coverts 60% of energy to light 45% which is the most efficient and what happens to the rest of the energy

2 answers:

Leya [2.2K]3 years ago

5 0

Answer:

The first one (60%)

Explanation:

The first one converts 15% more energy than the other one. Therefore, it is more efficient.

Hope this helps!

Hitman42 [59]3 years ago

4 0

Answer:60% one is the most efficient one

Explanation: First one is given 60% of light energy out of 100% and second one is given 45% light energy out of 100%. Waste of first one is 40% and second one is 55% .

Then those waste energy is transfer to the heat energy.

When you touch the bulb you feel hot . Its because of heat energy. If the heat loss is less . Bulb is more efficient

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$n$ and $q$ are the same for all four samples, for they are made out of the same material.

As a result, $I$ of each wire is directly proportional to $v \cdot r^{2}$ where the value of $\pi \cdot n \cdot q$ is constant.

For each of the four wires:

$\begin{array}{ccc|c}\\& r & v &I \propto v\cdot r^{2}\\a) & 3 & 1 & 9\\b) & 4 & 0.5 & 8\\c) & 1 & 5 & 5\\d) & 2 & 2.5 & 10\\\end{array}$ .

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