Answer:
the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin.
Explanation:
As described in activity 1, the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin. Urea basically is an heavy compound, thus it is at the base of the chain reactions which which major purpose is to break down the amino acids that make up proteins. Albumin on the other hand is a form of protein that simply helps in the transmission of blood and prevent blood from flowing through to other tissue in the body. The liver produces the albumin the body. So going back to the question, the major difference between the rate of diffusion between urea and albumin is that urea diffused more slowly because it is larger than albumin.
Answer:
Particle spacing increases and it's called evaporating
Answer:
Frequency
Explanation:
The property of waves that remains unchanged as it crosses the boundary of one medium to another is the frequency of the wave.
As a wave moves from one boundary to another, the wavelength and the speed of the wave changes.
The speed of the wave is product of wavelength and frequency. Also, the wavelength of the wave is function of the distance between successive crests or troughs of a wave.
The frequency of a wave is the number of waves that crosses a medium per unit of time.
Answer:
e. The amount of the charge decreases, because the capacitance decreases.
Explanation:
The capacitance of a parallel plate capacitor is given by the formula:
where 
is the permittivity of the medium between the plates, A the area of the plates and d the separation between them, so <em>if we increase the separation d the capacitance C will decrease</em>.
The relationship between the charge on the plate Q and the voltage applied V (the potential difference between the plates) is given by:
This means that if while <em>keeping the potential difference between the plates V constant the capacitance C decreases then the charge Q will decrease as well</em>.
