Tính lực tương tác giữa 2 điện tích q1=4.10^-6C và q2=-3.10^-6C cách nhau một 3cm đặt trong dầu hoả = 2
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1) The braking force is provided by the frictional force, which is given by:
where
is the coefficient of friction
m=1500 kg is the mass of the car
is the gravitational acceleration
Substituting numbers into the equation, we find
2) The work done by the frictional force to stop the car is equal to the product between the force and the distance d:
(1)
where we put a negative sign because the force is in the opposite direction of the motion of the car.
3) For the work-energy theorem, the work done by the frictional force is equal to the variation of kinetic energy of the car:
(2)
The final kinetic energy is zero, so the variation of kinetic energy is just equal to the initial kinetic energy of the car:
4) By equalizing eq. (1) and (2), we find the distance, d:
Answer:
Explanation:
At the beginning, we have:
V = 4.0 V potential difference across the capacitor
charge stored on the capacitor
Therefore, we can calculate the capacitance of the capacitor:
Later, the battery is replaced with another battery whose voltage is
V = 5.0 V
Since the capacitance of the capacitor does not change, we can calculate the new charge stored:
Since the capacitor has been connected exactly as before, we have that the charge on the positive plate has increased from to
. Therefore, the additional charge that moved to the positive plate is