A tree trunk is pulled with a force of 3200 pounds by a truck’s cable that makes an angle of 25° with the horizontal. What is th
e vertical component of the force correct to the nearest pound?
1 answer:
Answer:
The vertical component of the force correct to the nearest pound Is
1352 pound
Step-by-step explanation:
Kindly find attached for your reference
This problem bothers on the topic of work energy and power
Given data
Applied force = 3200 pounds
Angle of application = 25°
We know that the horizontal force =
F= 3200cos 25°
Hence the vertical component of this force = F= 3200sin 25
=3200*0.42261
= 1352.352
to the nearest pound
F = 1352pound
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A. Factor the numerator as a difference of squares:
c. As
, the contribution of the terms of degree less than 2 becomes negligible, which means we can write
e. Let's first rewrite the root terms with rational exponents:
![\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto1%7D%5Cfrac%7B%5Csqrt%5B3%5Dx-x%7D%7B%5Csqrt%20x-x%7D%3D%5Clim_%7Bx%5Cto1%7D%5Cfrac%7Bx%5E%7B1%2F3%7D-x%7D%7Bx%5E%7B1%2F2%7D-x%7D)
Next we rationalize the numerator and denominator. We do so by recalling
In particular,
so we have
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and 
, we can simplify the first term:
So our limit becomes
c. As
e. Let's first rewrite the root terms with rational exponents:
Next we rationalize the numerator and denominator. We do so by recalling
In particular,
so we have
For
So our limit becomes