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Serggg [28]
3 years ago
8

Given an acidic solution with a pH of 4.5, what is pOH of the same solution?

Chemistry
1 answer:
Crazy boy [7]3 years ago
8 0

Answer: Option C) 9.5

Explanation:

Given that,

pOH of solution = ?

pH of solution = 4.5 (it is an acidic solution because any pH values less than 7.0 is said to be acidic)

Recall that pH is the negative logarithm of hydrogen ion concentration in the solution while pOH is the negative logarithm of hydroxide ion concentration in the solution.

Hence, pH + pOH = 14

4.5 + pOH = 14

pOH = 14 - 4.5

pOH = 9.5

Thus, the pOH of the same solution is 9.5

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56.2÷6.02×10^23

=9.34×10^23

Explanation:

Divide the given mass of the atom by the mass of an Atom (the avogadro's constant) to find the number of atoms in the given mass.

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Diatoms are made of _____, which is used for industrial processes. calcium chitin silica cellulose
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The NaCl crystal structure consists of alternating Na⁺ and Cl⁻ ions lying next to each other in three dimensions. If the Na⁺ rad
Yuliya22 [10]

Answer : The radii of the two ions Cl⁻ ion and Na⁺ ion is, 181 and 102 pm respectively.

Explanation :

As we are given that the Na⁺ radius is 56.4% of the Cl⁻ radius.

Let us assume that the radius of Cl⁻ be, (x) pm

So, the radius of Na⁺ = x\times \frac{56.4}{100}=(0.564x)pm

In the crystal structure of NaCl, 2 Cl⁻ ions present at the corner and 1 Na⁺ ion present at the edge of lattice.

Thus, the edge length is equal to the sum of 2 radius of Cl⁻ ion and 2 radius of Na⁺ ion.

Given:

Distance between Na⁺ nuclei = 566 pm

Thus, the relation will be:

2\times \text{Radius of }Cl^-+2\times \text{Radius of }Na^+=\text{Distance between }Na^+\text{ nuclei}

2\times x+2\times 0.564x=566

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The radius of Cl⁻ ion = (x) pm = 181 pm

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C. physical change

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That's the answer

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