All categories

3 years ago

Is a red color a physical or chemical property

Chemistry

1 answer:

Nina [5.8K]3 years ago

7 0

It is a physical property

Color odour and taste are a properties that are detected by sense organs.

You might be interested in

Balance the equation below and pick the choice with the correct coefficients

stealth61 [152]

Answer:

Explanation:D

5 0

2 years ago

M → M+ + e- reduction or oxidation?

Julli [10]

That would be oxidation.

Oxidation is loss of electrons
Reduction is gain of electrons

4 0

2 years ago

How are electromagnetic waves different from mechanical waves?

Andreyy89

Answer:

Electromagnetic waves can travel through empty space; mechanical waves can not

Explanation:

The salient differences between electromagnetic waves and mechanical waves is that electromagnetic waves can travel through empty spaces but mechanical waves cannot.

Mechanical waves always requires a material medium for their propagation. No known mechanical waves can pass through an empty vacuum.

Electromagnetic waves on the other hand can pass through vacuum. They do not require a material medium for propagation.

This makes them unlimited in their form and mode of propagation.

3 0

2 years ago

A student dissolves of ammonia in of a solvent with a density of . The student notices that the volume of the solvent does not c

lidiya [134]

Answer:

1.2 M

1.2 m

Explanation:

There is some info missing. I think this is the original question.

A student dissolves 5.1g of ammonia (NH₃) in 250 mL of a solvent with a density of 1.02 g/mL. The student notices that the volume of the solvent does not change when the ammonia dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.

Molarity

The molar mass of ammonia is 17.03 g/mol. The moles corresponding to 5.1 grams is:

5.1 g × (1 mol/17.03 g) = 0.30 mol

The volume of the solution is equal to the volume of the solvent, 250 mL or 0,250 L.

The molarity of ammonia is:

M = moles of solute / liters of solution

M = 0.30 mol / 0.250 L

M = 1.2 M

Molality

The density of the solvent is 1.02 g/mL. The mass corresponding to 250 mL is:

250 mL × 1.02 g/mL = 255 g = 0.255 kg

The molality of ammonia is:

m = moles of solute / kilograms of solvent

m = 0.30 mol / 0.255 kg

m = 1.17 m ≈ 1.2 m

4 0

2 years ago

determine the number of atoms of each element in an empirical formula of a compound with the following composition:67.09% carbon

vfiekz [6]

Answer: The empirical formula for the given compound is $C_8H_{15}O_2$

Explanation:

We are given:

Percentage of C = 67.09 %

Percentage of H = 10.56 %

Percentage of O = 22.35 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 67.09 g

Mass of H = 10.56 g

Mass of O = 22.35 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{67.09g}{12g/mole}=5.59moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{10.56g}{1g/mole}=10.56moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{22.35g}{16g/mole}=1.40moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.40 moles.

For Carbon = $\frac{5.59}{1.40}=3.99\approx 4$

For Hydrogen = $\frac{10.56}{1.40}=7.5$

For Oxygen = $\frac{1.40}{1.40}=1$

Multiplying the mole ratio by '2' to make the mole ratios a whole number

Mole ratio of Carbon = (4 × 2) = 8

Mole ratio of Hydrogen= (7.5 × 2) = 15

Mole ratio of Oxygen = (1 × 2) = 2

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 8 : 15 : 2

In the compound, there are 8 atoms of carbon, 15 atoms of hydrogen and 2 atoms of oxygen

Hence, the empirical formula for the given compound is $C_8H_{15}O_2$

5 0

2 years ago