Question

A group of 18 people ordered soup and sandwiches for lunch. Each person in the group had either one soup or one sandwich. The sandwiches cost $7.75 each and the soups cost $4.50 each. If the total cost of all 18 lunches was $113.50, how many sandwiches were ordered?

Answer 1

Lets do this:-

A. 7 Sandwiches

18 - 7 = 11

7 × $7.75 =  $54.25
7 sandwiches cost $54.25.

11 × $4.50 = $49.50
11 soups costs $49.50

49.50 + 54.25 = 103.75
A is not d answer cuz d total of d lunches came to $113.50. 

B. 8 sandwiches

18 - 8 = 10

8 × $7.75 =  $62
8 sandwiches cost $62.

10 × $4.50 = 45
8 soups costs $45

62 + 45 = 107

B is not d answer cuz d total of d lunches came to $113.50. 

C. 9 Sandwiches.

18 - 9 =  9

9 × $7.75 = 69.75
9 sandwiches cost $69.

9 × $4.50 = 40.50
9 soups costs $40.50

69 + 40.50 = 109.5

C is not d answer cuz d total of d lunches came to $113.50. 

D. 10 Sandwiches

18 - 10 = 8

10 × $7.75 = $77.75
10 sandwiches cost $77.75.

8 × $4.50 = $36
8 soups costs $36.

77.75 + 36 = 113.75

D is not d answer cuz d total of d lunches came to $113.50. 

So, based on your answer choices there is no correct choice.