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3 years ago

How to you convert fractions into decimals

Mathematics

2 answers:

Viefleur [7K]3 years ago

5 0

Look at this photo it will help I know it will

bazaltina [42]3 years ago

5 0

You try to make the decimal closest to the tenths,hundredths, or thousandths

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What is the equation of this line in slope-intercept form?

KatRina [158]

Answer: B

Step-by-step explanation:

The slope-intercept is usually written as y = mx + b form, where m is the slope, and b is the y-intercept. The y-intercept is the y value when x is equal to 0.

We can first eliminate C, because the y-intercept of the graph is 1.

To solve for slope, which is the m, choose two points, (-1, 5) and (1, -3).

Slope = (y2 - y1) / (x2 - x1)

= (-3 - 5) / (1 - (-1))

= (-3 - 5) / (1 + 1)

= -8/2

= -4

Plug in the slope and y-intercept, we get y = -4x + 1

5 0

3 years ago

8. Sven sells hamburgers at a ballpark. He earns $14.50/h, plus $0.50

Komok [63]

Answer:

Part A: $55.50

Part B: 52 hamburgers(sorry if I am wrong for part b but I think it is right)

Step-by-step explanation:

Part A: $14.50 x 3= $43.50 + 24 x $0.50= $12=

($ earned per hrs x hrs worked)+ ($ per hamburger sold x times amount)

Hence $43.50 + $12= $55.50.

Part B: $14.50 x 6.5 = $94.25 $120 - $94.25= $25.75

($ earned per hrs x hrs worked x x hrs worked) ($ earned - $ earn from shif

$25.75/0.50=51.5 (51.5 rounded to nearest burgers is 52 burgers)

Hence answer is 52 burgers.

Please rate Good and mark Brainliest

Thank You

5 0

3 years ago

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$