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2 years ago

Which number is greater and by how much?

Mathematics

1 answer:

Lana71 [14]2 years ago

4 0

Answer:

Step-by-step explanation:

first option, as the decrease percentage is applicated on a greater number than the original

e.g.

a= 10

10 + 50% = 15

15 - 50% = 7,5

A will be greater then B by 25%

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What is 17 times 5 decided by 8

alekssr [168]

17x5/8 is 10.6 i believe

8 0

2 years ago

What two rational expressions sum to <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%2B2%7D%7Bx%5E%7B2%7D-9%2B8%20%7D" id="TexFor

bulgar [2K]

Answer:

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

Step-by-step explanation:

Given

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

Required

Fill in the gaps

Going by the given parameters, we have that

$\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}$

$x^2 - 9x + 8$ , when factorized is $(x-1)(x-8)$

Hence; the expression becomes

$\frac{4x+2}{(x-1)(x-8)} = \frac{A}{(x-8)(x-1)} + \frac{B}{(x-1)(x-8)}$

Combine Fractions

$\frac{4x+2}{(x-1)(x-8)} = \frac{A + B}{(x-8)(x-1)}$

Simplify the denominators

$4x + 2 = A + B$

By direct comparison

$A = 4x$

$B = 2$

Hence, the complete expression is

$\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}$

3 0

3 years ago

Read 2 more answers

Question 3. Solve each equation given<br>below.<br>5 x - 4=31

harkovskaia [24]

Answer:

x = 7

Step-by-step explanation:

5x-4 = 31

5x = 31+4

5x = 35

x = 7

3 0

3 years ago

If a 16-foot silo casts a 12-foot shadow, what is the measure from the tip of the shadow to the top of the silo? 20 feet 400 fee

wlad13 [49]

Use the pythagorean theorm

16^2 + 12^2 = c^2
256 + 144 = c^2
400 = c^2
c = 20 feet or a

4 0

3 years ago

Why infinity ( ) can’t be included in an inequality?

Ksju [112]

Answer:

Step-by-step explanation:

Because then the value on the other side will be unbounded by the infinity sign while expressing the answers on a number line.

please click thanks and mark brainliest if you like :)

7 0

3 years ago