Question

Consider the terms in the sequence: {4,32,256,2048,16,384,…}

Answer 1

Answer:

Common ratio is 8.

First term is 4

Recursive:

$a_n=8a_{n-1} \: a_1 = 4$

Step-by-step explanation:

The given sequence is:

{4,32,256,2048,16,384,…}

The common ratio of this sequence is obtained by dividing a term in the sequence by a previous term.

This is given by:

$r = \frac{32}{4} = 8$

The term of the sequence is the term that begins the sequence.

This is 4.

The recursive definition is given by:

$a_n=ra_{n-1}$

This implies that:

$a_n=8a_{n-1} \: a_1 = 4$