If the original side length is "s" and the original slant height is "h", the original surface area is
.. S = (base area) +(lateral area)
.. S = s² +(1/2)*(4s)*h
.. S = s(s +2h)
Now, if we make these replacements: s ⇒ 3s, h ⇒ h/5, we have
.. S' = (3s)(3s +2h/5)
.. S' = 9s² +(6/5)s*h . . . . . . . the formula for the modified area (in terms of original dimensions)
_____
Of course, in terms of the modified dimensions, the formula is the same:
.. S' = s'(s' +2h')
Answer:
4 inches should be turned up on both sides.
Step-by-step explanation:
In order to find this, create a situation in which we give the amount turned up on each side as x. Then give the amount that isn't turned up as 16 - 2x (since 2x is the amount turned up). Now we can find the area by multiplying the 3 measurements.
100 * x * (16 - 2x) = MAX
100 * (16x - 2x^2) = MAX
-200x^2 + 1600x = MAX
Now that we have a quadratic function, we can find the maximum value of x by using the vertex formula for x values (-b/2a).
x = -b/2a
x = -1600/2(-200)
x = -1600/-400
x = 4
You haven't provided the expression or the choices, therefore, I cannot provide an exact answer.
However, I'll try to help you understand the concept so that you can solve the question you have
Like radicals are characterized by the following:1- They both have the same root number (square root, cubic root , ...etc)
2- They both have the same radicand (meaning that the expression under the root is the same in both radicals)
Examples of like radicals:3

and 7

![\sqrt[5]{x^2y}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7Bx%5E2y%7D%20)
and 3
![\sqrt[5]{x^2y}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7Bx%5E2y%7D%20)
Check the choices you have. The one that satisfies the above two conditions would be your correct choice
Hope this helps :)
Y=4 and I'm not sure on the second one sorry
Answer:
whats the question love?
Step-by-step explanation: