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Jet001 [13]
3 years ago
15

Many organisms have adaptations which allow them to live in certain environments.

Chemistry
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

Webbed Feet

Explanation:

<em><u>Webbed Feet Benefits:</u></em>

Most animals with webbed feet are aquatic animals who live in, on, or near the water. Webbed feet help them <em>move quickly</em> through the water when they're chasing food or trying to escape from predators.

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What is the order of the phases on a heating curve
Aloiza [94]
Hope this helps!!!! Here is a diagram

6 0
3 years ago
Show the calculation of the mole fraction of each gas in a 1.00 liter container holding a mixture of 8.65 g of CO2 and 4.32 g of
Vlad1618 [11]

Answer:

0.745 and 0.245

Explanation:

Mole fraction (χ) is  the number of moles of a component divided by the total number of moles in a mixture.  

We must calculate the moles of each component.  

Let CO₂ be Gas 1 and SO₂ be Gas 2.

1. Calculate the moles of each gas.

\text{n} _{1} = \text{8.65 g} \times \dfrac{\text{1 mol}}{\text{44.01 g}} = \text{0.1965 mol}\\\\\text{n} _{2} = \text{4.32 g} \times \dfrac{\text{1 mol}}{\text{64.06 g}} = \text{0.067 44 mol}

2. Calculate the total moles.

n_{\text{tot}} = \text{n}_{1} + \text{n}_{2} = \text{0.1965 mol} +\text{0.067 44 mol} = \text{0.2640 mol}

3. Calculate the mole fraction of each component

\chi_{1} =\dfrac{0.1965}{0.2640} = \mathbf{0.745}\\\\\chi_{2} =\dfrac{0.06744}{0.2640} = \mathbf{0.255}

6 0
3 years ago
How many moles of each element (C, H, and O) are present in a 100.0 g sample of<br> ethanol?
Anuta_ua [19.1K]

Answer:

2.173 moles of ethanol is presented in a 100.0g sample of ethanol .

Explanation:

The amount of substance that contains as many Particles as there are atoms in exactly 12g of carbon- '12 isotope is called 1 mole '= 46 u.

7 0
3 years ago
Your lab partner accidentally spills some acid on his wrist and watchband. You should: (Check all that apply.)
nordsb [41]

Answer: Remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. Let the TA inspect his wrist to see if it is okay.

Explanation:

The question is incomplete, the choices are:

a. Take him to the safety shower, and make sure he stands under it for at least 15 minutes to be sure all hazardous material has been washed away. b. Remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. c. Let the TA inspect his wrist to see if it is okay.

d. Rinse the watch band before allowing him to put it back on.

An acid is traditionally considered to be any chemical compound that, when dissolved in water, produces a solution with greater hydronium cation activity than pure water, i.e., a pH less than 7. Both corrosive acids (and also corrosive bases) <u>are capable of destroying skin</u> by catalyzing the hydrolysis of fats, which are chemically esters. Also, when acids attack metals, hydrogen gas is often released.

This is why your lab partner should remove the watch and watchband immediately, and rinse his wrist for at least 15 minutes to be sure all hazardous material has been washed away. This ensures that the acid is can not damage the skin. And also the person should make sure that someone qualified checks it to see if it is okay.

7 0
4 years ago
How many atomic orbitals of each type mix to form hybrid orbitals of the central atom in cl2o?
lidiya [134]

In here Oxygen is the central atom. It makes two bonds with Cl and has two lone pairs. Since, the shape is bent and the hybridization is sp3. Molecular geometry is a bit dissimilar from hybridization. Hybridization is reliant on the number of bonds and lone pairs. Since O has two bonds with Cl, its hybridization is sp3. It is like is this: 1 lone pair/bond = s. 2 lone pairs/bond = sp 3 lone pairs/bonds = sp2, etc. molecular geometry, you count the number of bonds and lone pairs. This has two bonds and 2 lone pairs so if they were all bonds, the molecule would be tetrahedral. 

4 0
4 years ago
Read 2 more answers
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