Explanation:
It is known that molality is the number of moles present in kg of solution.
Mathematically, Molality = 
The given data is as follows.
Molar mass of ammonia = 17 g/mol
Concentration = 1.002 mg/L = 
= 
mol/L
Also, density = 
= 1 kg/L
Therefore, molality will be calculated as follows.
Molality = 
= 
And,
Molar mass of nitrite = 46 g/mol
Concentration = 0.387 mg/L = 
= 
mol/L
And, density = = 1 kg/L
Hence, molality = 
= mol/kg
Now, Molar mass of nitarte = 62 g/mol
Concentration = 1352.2 mg/L
= 
= 0.02181 mol/L
Also, density = = 1 kg/L
Hence, molality will be calculated as follows.
Molality = 
= 0.02181 mol/kg
Therefore, molality of given species is for ammonia, mol/kg for nitrite, and 0.02181 mol/kg for nitrate ion.
Answer:
the stem, but if its more specific xylem cells
Freezing Point of Sea water would be lower than that of Pure Water. It is because of salinity of the water
Hope this helps!
Answer:
Mass = 0.697 g
Explanation:
Given data:
Volume of hydrogen = 1.36 L
Mass of ammonia produced = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
First of all we will calculate the number of moles of hydrogen:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K
1.36 atm.L = n × 22.43 atm.L/mol
n = 1.36 atm.L / 22.43 atm.L/mol
n = 0.061 mol
Now we will compare the moles of hydrogen and ammonia:
H₂ : NH₃
3 : 2
0.061 : 2/3×0.061 = 0.041
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.041 mol × 17 g/mol
Mass = 0.697 g
Answer: False
Explanation:
4C2H6 + 7O2 --> 6H2O + 4CO2
8 Carbons on the reactant side, but 4 Carbons on the Product
24 Hydrogens on Reactant, 12 H on product
But Oxygen is balanced, 14 on each side
