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4 years ago

Calculate number of grams in 1.15*10^21 molecules of P2O5

1 answer:

6 0

To go from molecules, we first need to convert to moles and then convert to grams.

To convert from molecules to moles, we need to divide by Avogadro's constant.

1.15*10^21 molecules * (1 mole/6.022*10^23 molecules) = 0.0019097 moles

To convert from moles to grams, we need to use the molar mass.

The molar mass of P₂O₅ is (2*30.98)+(5*16.00) = 141.96
You can find the molar mass using the periodic table.

0.0019097 moles * (141.96 grams/1 mole) = 0.2711 grams.

Since we have 3 significant digits in 1.15*10^21, that means our final answer is limited to 3 significant digits.

Your final answer is 0.271 grams.

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Write the symbol for every chemical element that has atomic number greater than 3 and atomic mass less than 15.4 u.

mixas84 [53]

Answer:

N, B, Be, C

Explanation:

N (Nitrogen) has 14.0067 B (Boron) has 10.81 Be (Beryllium) has 9 and C (Carbon) has 12

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2 years ago

The rate of decomposition of N2O5 in CCl4 at 317 K has been studied by monitoring the concentration of N2O5 in the solution. 2 N

pav-90 [236]

Answer:

Average rate of reaction is 0.000565 M/min

Explanation:

Applying law of mass action for the given reaction:

Average rate = $-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO_{2}]}{\Delta t}=\frac{\Delta [O_{2}]}{\Delta t}$

Where, $-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}$ represents average rate of disappearance of $N_{2}O_{5}$ , $\frac{1}{4}\frac{[NO_{2}]}{\Delta t}$ represents average rate of appearance of $NO_{2}$ and $\frac{[O_{2}]}{\Delta t}$ represents average rate of appearance of $O_{2}$

Here, $-\frac{[N_{2}O_{5}]}{\Delta t}$ = $-\frac{(2.16-2.36)}{(177-0)}M/min=0.00113M/min$

So average rate of reaction = $[tex]-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}$ [/tex] = $\frac{1}{2}\times (0.00113M/min)=0.000565M/min$

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3 years ago

What is the periodic element symbol for gold?

Makovka662 [10]

Gold is Au on the periodic table

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4 years ago

Select the correct answer.

Sladkaya [172]

Answer:

Option D. There will be a shift toward the reactants.

Explanation:

The reaction is:

$PCl_5(g)+heat\rightleftharpoons PCl_3(g)+Cl_2(g)$

The application of LeChatelier's principle leads to consider the heat as a reactant or a product depending on if it is on the left side or the right side.

In this reaction, the heat is on the left side, thus it must be considered a reactant.

Decreasing the temperature is equivalent to remove or consume heat. Thus, the reaction must shif to the left to compensate that reduction of heat. That is the reverse reaction shall be favored.

In conclusion, there will be a shift toward the reactants.

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4 years ago