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Nataly [62]
3 years ago
10

Frank joined a fitness club. He paid a $50 registration fee, and dues are $12 per month. Which expression can be used to find th

e average monthly cost of an x-month membership at the club?
Mathematics
2 answers:
fenix001 [56]3 years ago
8 0
Each month, Frank pays $12, which is represented by the equation 12x, with x the number of months.
And to know how much he Pay in total, we add 50 dollars to the 12x.
So the problem can be represented by the equation: 12x + 50.

Hope this Helps! :)
atroni [7]3 years ago
7 0

Answer: The expression will be \frac{50+12x}{x}

Step-by-step explanation: Frank has to pay $50 as the registration fee. This amount is compulsory to be paid

Step 1: Dues for $12 months

Let the due to be paid every month be $x, so dues to be paid for 12 months will be 12x

Step 2: Expression for the average monthly cost for x-month will be

Expression: \frac{\text{Total cost}}{\text{Total months}}

Total cost = 50 + 12x

Expression: \frac{50+12x}{x}

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The sum of the digits of a two-digit number is 8. If the digits are interchanged ,new number is 10 more than double the original
vova2212 [387]

Answer:

Original number 26.

Step-by-step explanation:

xy - two-digit number

1) x + y = 8

2) Original two-digit number can be written as

10*x + y

3) If the digits interchanged yx,

then the new number can be written as

10*y + x

4)  Double the original number is

2*(10*x + y)

5) New number is 10 more than double the original number

(10*y + x) - (2*(10*x + y)) = 10

6) Now we have the system of 2 equations:

x + y = 8

(10*y + x) - (2*(10*x + y)) = 10 -----> 10y + x - (20x + 2y) = 10 ---> 8y - 19x = 10

x = 8 - y

8y - 19(8 - y) = 10

8y - 152 +19y = 10

27y = 162

y = 6

x = 8 - y = 8 - 6 = 2

x = 2

So, x =2, y = 6.

Original number 26.

Check:

Original number 26.

New number 62.

Double of the original number = 2*26= 52.

New number is 10 more than double the original number :

62 - 52 = 10 True

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Which numbers are a distance of 4 units from 7 on the number line
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Step-by-step explanation:

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2 years ago
A personnel director in a particular state claims that the mean annual income is the same in one of the​ state's counties​ (Coun
Shalnov [3]

Answer:

a) The hypothesis that the mean annual income is the same could not be rejected. There is no enough evidence to claim they are different.

b) The critical values for this two-sided test are t=±1.711.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>(a) Identify the claim and state  H0  and  Ha. </em>

<em> Which is the correct claim​ below?</em>

<em>(b) Find the critical​ value(s) and identify the rejection​ region(s). </em>

<em> Enter the critical​ value(s) below.</em>

We have an hypothesis test on the difference of two means.

The null and alternative hypothesis are:

H_0: \mu_a-\mu_b=0\\\\H_a: \mu_a-\mu_b\neq 0

The claim of the alternative hypothesis is that the mean annual income is different in County A and County B.

The null hypothesis is that the mean annual income is equal in both counties.

The significance level is α=0.10.

The sample from County A has a mean of S40,400, a s.d. of $8,700 and a sample size of 18 residents.

The sample from County B has a mean of S39,200, a s.d. of $6,000 and a sample size of 8 residents.

The standard error of the difference of means is:

\sigma_d=\sqrt{\frac{\sigma_a^2}{n_a}+\frac{\sigma_b^2}{n_b}}=\sqrt{\frac{8700^2}{18}+\frac{6000^2}{8}}=\sqrt{8705000}=2950

The degrees of freedom are:

df=n_a+n_b-2=18+8-2=24

Then, the test statistic is:

t=\frac{\Delta M-\Delta \mu}{\sigma_d} =\frac{(40,400-39,200)-0}{2950} =\frac{1200}{2950}=0.407

For a statistic t=0.407, and df=24, the P-value is P=0.69. As the P-value is bigger than the significance level, the null hypothesis failed to be rejected.

If we would use the critial value approach, we would have to calculate the critical values for t, for df=24, two sided test and α=0.10.

The critical values, looking in a table, are t=1.711.

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3 years ago
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