Answer:
0.229 seconds
Explanation:
Given:
y₀ = 80.6 m
v₀ = 0 m/s
a = -9.8 m/s²
We need to find the difference in times when y = 10.8 m and y = 2.10 m.
When y = 10.8 m:
y = y₀ + v₀ t + ½ at²
10.8 = 80.6 + (0) t + ½ (-9.8) t²
10.8 = 80.6 − 4.9 t²
4.9 t² = 69.8
t = 3.774
When y = 2.10 m:
y = y₀ + v₀ t + ½ at²
2.10 = 80.6 + (0) t + ½ (-9.8) t²
2.10 = 80.6 − 4.9 t²
4.9 t² = 78.5
t = 4.003
The difference is:
4.003 − 3.774 = 0.229
The man has 0.229 seconds to get out of the way.
Explanation:
first rule of parallel circuits : the voltage is the same in the whole circuit, no matter where we measure.
so, we have 1.5V at every bulb.
second rule of parallel circuits : the total current is the sum of the individual branch currents.
so, if the battery really allows it, then we have 3 times 0.4 A = 3×0.4 = 1.2 A as current in the circuit.
I would say that this passage is an example of the heliocentric correct view of the world with the sun and not the earth the center of our universe and this formed a very important part of the Renaissance wherein nature was examined first hand wherever possible to arrive at a much closer approximation of the truth than in Medieval or Classical times of Aristotle when idle speculation about nature was the order of the day.
Answer:
Input impedance of this transformer is 50 ohms.
Explanation:
Given that,
Number of turns in the primary coil, 
Number of turns in the secondary coil, 
Output impedance of the transformer, 
The number of turns and the impedance ratio in the step down transformer is given by :
So, the input impedance of this transformer is 50 ohms. Hence, this is the required solution.
Answer:
The temperature change in the calorimeter will be lower
Explanation:
Water is an example of a molecular substance. They have relatively low melting points and boiling points usually below 300° C . Water reacts with metals to a degree varying with their position in the electrochemical series.
The specific heat of water is 4179.6 Joules which is relatively high . This typically implies that water absorbs a larger amount of heat but the increase in temperature of its boiling points is relatively low. Thus; in the 200-mm test tube that contains water and was subsequently added to the calorimeter , the heat present was initially absorbed by the water and that does not result to an increase in the temperature change in the calorimeter. Thus the temperature change in the calorimeter will be lower.
