Differentiate it
get f ' (x)=3x^2-4
put 3x^2-4=0
x=2/√3,-2/√3
so interval
x∈(-2/√3,2/√3)
The only thing you need to do is divide 56 by -7. You know the d must be a negative number because negative x negative= positive. So 56 / -7 is -8.
Answer: What is the question?
I believe the greatest common divisor would be 6.
hope this helps you! :-)
The discriminant can be found using the formula b^2-4ac
First put your equation in standard form, where all your values are on one side, and just add f(x) or y in front of your equation.
y= 8p^2-8p+2
The first value of your equation is a (a=8)
The second term of your equation is b (b=-8)
The last term of your equation is c (c=2)
Plug in the values to the discriminant equation b^2-4ac