Answer:
30.3 g
Explanation:
At STP, 1 mol of any gas will occupy 22.4 L.
With the information above in mind, we <u>calculate how many moles are there in 32.0 L</u>:
- 32.0 L ÷ 22.4 L/mol = 1.43 mol
Then we <u>calculate how many moles would there be in 16.6 L</u>:
- 16.6 L ÷ 22.4 L/mol = 0.741 mol
The <u>difference in moles is</u>:
- 1.43 mol - 0.741 mol = 0.689 mol
Finally we <u>convert 0.689 moles of CO₂ into grams</u>, using its <em>molar mass</em>:
- 0.689 mol * 44 g/mol = 30.3 g
The de Broglie wavelength of a subatomic particle is 2.09 nm.
λ = h m v = h
momentum : wherein 'h' is the Plank's steady. This equation pertaining to the momentum of a particle with its wavelength is de Broglie equation and the wavelength calculated the use of this relation is de Broglie wavelength.
Frequency is the ratio of velocity and wavelength in relation to hurry. In evaluation, wavelength refers back to the ratio of velocity and frequency.
Wavelength is the gap between the crests of waves or a person's fashionable mind-set. An instance of wavelength is the gap between the crest of two waves. An instance of wavelength is while you and some other character share the equal standard attitude and might for that reason speak properly.
calculation is given in the image below
de Broglie wavelength λ = h/mv
= (6.626 * 10^-34)/9.1 * 10^-31 *351 *10^3
= 2.07 *10^-9
Hence, = 2.op nm
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The given alkyne is Option A 3-heptyne
<h3>
What is an Alkyne ?</h3>
The hydrocarbon having at least one C-C triple bond is called an Alkyne.
It has the general formula of 
.
In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.
It has been asked in the question that
CH3CH₂C ≡ CCH₂CH₂CH3 is which alkyne from the given option.
The counting of the Carbon chain is done from the left side and the Triple bond is at the 3rd Carbon , so 3-heptyne .
To know more about Alkyne
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