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4 years ago

Can 1 be an additive identity?

1 answer:

5 0

Hey there, Valensolar! I would usually explain my answer, but in this case, I cant use any of the symbols required. But the answer is no. The number 1 can NOT be an additive identity. I hope this helps! :D

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F(x)= squared x^2+7x+6

Temka [501]

Subtract
6
6
from both sides of the equation.
x
2
−
7
x
=
−
6
x
2
-
7
x
=
-
6
To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of
b
b
.
(
b
2
)
2
=
(
−
7
2
)
2
(
b
2
)
2
=
(
-
7
2
)
2
Add the term to each side of the equation.
x
2
−
7
x
+
(
−
7
2
)
2
=
−
6
+
(
−
7
2
)
2
x
2
-
7
x
+
(
-
7
2
)
2
=
-
6
+
(
-
7
2
)
2
Simplify the equation.
Tap for more steps...
x
2
−
7
x
+
49
4
=
25
4
x
2
-
7
x
+
49
4
=
25
4
Factor the perfect trinomial square into
(
x
−
7
2
)
2
(
x
-
7
2
)
2
.
(
x
−
7
2
)
2
=
25
4
(
x
-
7
2
)
2
=
25
4
Solve the equation for
x
x
.
Tap for more steps...
x
=
6
,
1

6 0

3 years ago

HELP 10 POINT FOR THIS EQUATION!

12345 [234]

Answer:The equivalent expression of the given terms is 13p

4 0

3 years ago

X^2-6x-4=0,

Rzqust [24]

Use quadratic formula since we can't factor

for 0=ax²+bx+c
$x= \frac{-b+/-\sqrt{b^2-4ac}}{2a}$

so, for
0=1x²-6x-4
a=1
b=-6
c=-4

$x= \frac{-(-6)+/-\sqrt{(-6)^2-4(1)(-4)}}{2(1)}$
$x= \frac{6+/-\sqrt{36+16}}{2}$
$x= \frac{6+/-\sqrt{52}}{2}$
$x= \frac{6+/-2\sqrt{13}}{2}$
$x= 3+/-\sqrt{13}$

the solutions are x=3+√13 and x=3-√13
or aprox
x≈6.61 and x≈-0.61

4 0

3 years ago

What are the vertex focus and directrix of the parabola with the given equation y=1/28(x-4)^2-5

patriot [66]

If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the y-axis, it has an equation of (x - h)^2 = 4p(y - k), where the focus is (h, k+p) and the directrix is y = k - p. So, we need to determine the values from the equation.

y=1/28(x-4)^2-5
(x-4)^2 = 28(y+5)
(h,k) = (4, -5)
p = 7

focus= (h, k+p) = 4,2
directrix = y = k - p = -12

Hope this answers the question.

8 0

3 years ago

Read 2 more answers

A dealer earns a profit of 8$ per bag of white cement and a loss of 5$ per bag of grey cement.

Natali [406]

Answer :-

loss = 1000$
4000

Step by step explanation :-

Profit on 3000 bags of white cement sold = 3000 × 8 = 24000

loss on 5000 bags of grey cement sold = 5000 × 5 = 25000

Alternatively: 

Net loss = ( 25000 - 24000 ) = 1000$
profit/ loss = $ [3000 × 8 - 5000 × 5 ]
$ [24000 - 25000]
-1000$

As the result of transaction is negative/ loss

Loss = 1000$

Loss on the scale of 6400 grey bags = 6400 × 5 = 32,000

In order to have no profit, profit from the Cello white cement should be 32000.

Number of white cement bags to be sold = 32000 / 8 = 4000

4000 why cement bags and 6400 grey cement bags are sold in order to have no profit and no loss

Hope it helps ~

5 0

2 years ago