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DerKrebs [107]
4 years ago
13

Can 1 be an additive identity?

Mathematics
1 answer:
Sphinxa [80]4 years ago
5 0
Hey there, Valensolar! I would usually explain my answer, but in this case, I cant use any of the symbols required. But the answer is no. The number 1 can NOT be an additive identity. I hope this helps! :D
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F(x)= squared x^2+7x+6
Temka [501]
Subtract
6
6
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x
2
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x
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6
To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of
b
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(
b
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=
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(
b
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2
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2
Add the term to each side of the equation.
x
2
−
7
x
+
(
−
7
2
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2
=
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6
+
(
−
7
2
)
2
x
2
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+
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Simplify the equation.
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x
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x
+
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4
=
25
4
x
2
-
7
x
+
49
4
=
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4
Factor the perfect trinomial square into
(
x
−
7
2
)
2
(
x
-
7
2
)
2
.
(
x
−
7
2
)
2
=
25
4
(
x
-
7
2
)
2
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6 0
3 years ago
HELP 10 POINT FOR THIS EQUATION!
12345 [234]

Answer:The equivalent expression of the given terms is 13p

4 0
3 years ago
X^2-6x-4=0,
Rzqust [24]
Use quadratic formula since we can't factor

for 0=ax²+bx+c
x= \frac{-b+/-\sqrt{b^2-4ac}}{2a}

so, for
0=1x²-6x-4
a=1
b=-6
c=-4

x= \frac{-(-6)+/-\sqrt{(-6)^2-4(1)(-4)}}{2(1)}
x= \frac{6+/-\sqrt{36+16}}{2}
x= \frac{6+/-\sqrt{52}}{2}
x= \frac{6+/-2\sqrt{13}}{2}
x= 3+/-\sqrt{13}

the solutions are x=3+√13 and x=3-√13
or aprox
x≈6.61 and x≈-0.61
4 0
3 years ago
What are the vertex focus and directrix of the parabola with the given equation <br> y=1/28(x-4)^2-5
patriot [66]
If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the y-axis, it has an equation of (x - h)^2<span> = 4p(y - k)</span><span>, where the </span>focus<span> is (h, k+p) and the </span>directrix<span> is y = k - p. So, we need to determine the values from the equation.

</span><span>y=1/28(x-4)^2-5
</span>(x-4)^2 = 28(y+5)<span>
(h,k) = (4, -5)
p = 7

focus= </span>(h, k+p) = 4,2
directrix = y = k - p = -12

Hope this answers the question.
8 0
3 years ago
Read 2 more answers
A dealer earns a profit of 8$ per bag of white cement and a loss of 5$ per bag of grey cement.
Natali [406]

Answer :-

  1. loss = <em> </em><em>100</em><em>0</em><em>$</em><em> </em>
  2. 4000

Step by step explanation :-

1#

Profit on 3000 bags of white cement sold = 3000 × 8 = 24000

loss on 5000 bags of grey cement sold = 5000 × 5 = 25000

<u>Alternatively</u><u>:</u><u> </u>

  • Net loss = ( 25000 - 24000 ) = 1000$
  • profit/ loss = $ [3000 × 8 - 5000 × 5 ]
  • $ [24000 - 25000]
  • -1000$

<em>As</em><em> </em><em>the</em><em> </em><em>result</em><em> </em><em>of</em><em> </em><em>transaction</em><em> </em><em>is</em><em> </em><em>negative</em><em>/</em><em> </em><em>loss</em><em> </em>

  • Loss = 1000$

2#

  • Loss on the scale of 6400 grey bags = 6400 × 5 = 32,000

<em>In</em><em> </em><em>order</em><em> </em><em>to</em><em> </em><em>have</em><em> </em><em>no</em><em> </em><em>profit</em><em>, </em><em> </em><em>profit from the </em><em>Cello </em><em>white cement should be 32</em><em>0</em><em>0</em><em>0</em><em>.</em><em> </em>

  • Number of white cement bags to be sold = 32000 / 8 = 4000

<em>4000 why cement bags and 6400</em><em> </em><em>grey</em><em> </em><em>cement</em><em> </em><em> </em><em>bags</em><em> </em><em>are sold in order to have no profit and </em><em>n</em><em>o</em><em> </em><em>loss </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>~</em>

5 0
2 years ago
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