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jonny [76]
4 years ago
5

There are eight pencils in a package. How many packages will be needed for 28 children if each child gets 4 pencils?

Mathematics
2 answers:
eduard4 years ago
6 0
14 packages
28(children) × 4(pencils) = 112(pencils)
112(pencils) ÷ 8(pencils per package) = 14(packages)
zimovet [89]4 years ago
3 0
Seven because 4x7 equals 28
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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

Therefore, AB must be exactly half of AD:

AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24

3 0
3 years ago
Read 2 more answers
Explain answer ! <br><br> Will give brainlst
Ne4ueva [31]

Answer:

x = 4, y = 2

Step-by-step explanation:

Start by multiplying the first equation by 2:

2x + 2y = 12 --> 4x + 4y = 24

Subtract the second from the first:

   4x + 4y = 24

-   5x + 4y = 28

4x - 5x = -x

4y = 4y = 0

24 - 28 = -4

so you end with -x + 0 = -4

Solve for x to get x = 4

Plug x = 4 back into 2x + 2y = 12 to find y.

2(4) + 2y = 12

8 + 2y = 12

2y = 4

y = 2

5 0
3 years ago
A square has a length of 4.8 feet. If the square is dilated by a factor of 4 , what is the length of a side of the new square? W
oksano4ka [1.4K]

Answer:

4.8x4=19.2, and then 19.2/4=4.8 feet

Each side would be 4.8 feet

8 0
3 years ago
Which of the following binomials is a factor of 22 + 7 −9 ?
Kipish [7]
B i think..............
8 0
3 years ago
Ivan has cut 19 pieces of reinforcing bar​ (rebar) that are each 1.14 meters long. What is the total length of the rebar used fo
madreJ [45]

Answer:

The total length of rebar used is  21.66 meters.

Step-by-step explanation:

Given:

Ivan had cut a reinforcing bar in 19 pieces and length of each bar is 1.14 meters.

Number of pieces = 19

Length of each piece = 1.14

We need to find the total length of reinforcing bar.

To calculate the total length we will multiply number of pieces with length of each piece.

Hence,

Total length of rebar = Number of pieces × Length of each piece = 19\times1.14 = 21..66 m

Rounding to nearest hundred = 21.66 m

Hence the total length of reinforcing bar is 21.66 meters.

4 0
3 years ago
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