The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Step-by-step explanation:
here,,
a=3,b=10,C=120°
c^2=a^2+b^2-2ab cos120°
=(3)^2 +(10)^2 _2 (3)(10)(-1/2) [cos120°=-1/2]
=9+100-(-30)
=109+30
=139
c=(139 )1/2=11.79
c=12
The answer is B. Use distance formula...
Answer:
1234588765
Step-by-step explanation:
Answer:
580 yards long.
Step-by-step explanation:
The distance of the walking tour is = 1 mile
Step 1
We have to convert 1 mile to yards
Therefore ,
1 mile = 1760 yards
Step 2
We are told that the group took a detour that was 300 yards shorter than half the distance of the tour.
The second step would be to find out how many yards is equal to half the distance of the tour.
Half the distance of the tour = 1/2 of a mile
And in step 1 we have converted whole distance of the tour to yards
= 1 mile = 1760 yards.
Hence, Half the distance of the tour = 1760 yards ÷ 2
= 880 yards.
Step 3
The group took a detour that was 300 yards shorter than half the distance of the tour.
This means mathematically,
Half the distance of the tour - 300 yards
= 880 yards - 300 yards
= 580 yards.
Therefore, the detour was 580 yards long.
