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NikAS [45]
3 years ago
7

Pls helpSolve 2/3x- 1/5>1 ​

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

x > 9/5

Step-by-step explanation:

Step 1: Write inequality

2/3x - 1/5 > 1

Step 2: Solve for <em>x</em>

  1. Add 1/5 to both sides: 2/3x > 6/5
  2. Divide both sides by 2/3: x > 9/5

Here we see that any <em>x</em> value greater than 9/5 will work.

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Let's say the numbers are "a" and "b"

now, we know one of them is 7 more than the other, so hmmm let's say "b" is 7 more than "a", so b = a + 7

the difference of their squares is 161, alrite

\bf a^2-b^2=161\qquad b=a+7\implies a^2-(a+7)^2=161&#10;\\\\\\&#10;a^2-(a^2+14a+49)=161\implies \underline{a^2-a^2}-14a-49=161&#10;\\\\\\&#10;-14a-49=161\implies -49-161=14a\implies -210=14a&#10;\\\\\\&#10;\cfrac{-210}{14}=a

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