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NikAS [45]
3 years ago
7

Pls helpSolve 2/3x- 1/5>1 ​

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

x > 9/5

Step-by-step explanation:

Step 1: Write inequality

2/3x - 1/5 > 1

Step 2: Solve for <em>x</em>

  1. Add 1/5 to both sides: 2/3x > 6/5
  2. Divide both sides by 2/3: x > 9/5

Here we see that any <em>x</em> value greater than 9/5 will work.

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Need help with this problem
Advocard [28]

Answer:

198

Step-by-step explanation:

If you take any 3-digit number and change the numbers around and subtract them you will always get 198.

7 0
3 years ago
In a triangle, the sum of the measures of the first two angles is 12 less than the measure of the third angle. In addition, the
USPshnik [31]

The measure of the three angles are  56, 28 , 192 degree

<h3>What is a Triangle ?</h3>

A triangle is a polygon with three sides , three vertices an three angles.

It is given to make system of equations

Let the measure of the first , second and third angle be x, y and z

the sum of the measures of the first two angles is 12 less than the measure of the third angle.

x +y = z -12  ----1

the measure of the first angle is twice as big as the measure of the second angle.

x = 2y

Now equation 1 will be

z - 3y = 12

x +y+z = 180

2y +y +z = 180

3y +z = 180 ----2

z - 3y = 12------3

On solving the system of equation 1, 2

2z = 192

z= 96 degree

3y = 180-96

y = 28

x = 56

Therefore the measure of the three angles area  56, 28 , 192 degree.

To know more about Triangle

brainly.com/question/2773823

#SPJ1

8 0
2 years ago
Sally, Sue and Joe were measured in gym class. Sally was 65 3/4 inches. Sue was 65 7/8 inches. Joe was 65 1/2 inches. Who was th
qaws [65]

Answer:

Sue was the tallest.

Step-by-step explanation:

Sally = 65 3/4 --> 65 6/8

<h2>Sue = <u>65 7/8</u></h2>

Joe = 65 1/2 --> 65 4/8

5 0
3 years ago
Find the area in square units ​
Dafna11 [192]

Answer: 24

Step-by-step explanation:

First count it all right 6 x 6 = 36

Then the squares inside are 4 x 3 = 12

36 - 12 = 24

I beilive that is your answer.

4 0
2 years ago
Which of the following are identities? Check all that apply
Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}

Double angle tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula sin2\alpha =2sin\alpha *cos\alpha

sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)

D) False No further development towards a Trig Identity

[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)

7 0
3 years ago
Read 2 more answers
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