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NikAS [45]
3 years ago
7

Pls helpSolve 2/3x- 1/5>1 ​

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

x > 9/5

Step-by-step explanation:

Step 1: Write inequality

2/3x - 1/5 > 1

Step 2: Solve for <em>x</em>

  1. Add 1/5 to both sides: 2/3x > 6/5
  2. Divide both sides by 2/3: x > 9/5

Here we see that any <em>x</em> value greater than 9/5 will work.

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Consider the function below. f(x) = 6x tan x, −π/2 &lt; x &lt; π/2 (a) find the vertical asymptote(s). (enter your answers as a
Molodets [167]

Answer: Does not exist.

Step-by-step explanation:

Since, given function,  f(x) = 6x tan x, where −π/2 < x < π/2.

⇒ f(x) = \frac{6x sin x}{cosx}

And, for vertical asymptote,  cosx= 0

⇒ x = π/2 + nπ where n is any integer.

But, for any n x is does not exist in the interval ( -π/2, π/2)

Therefore, vertical asymptote of f(x) where −π/2 < x < π/2 does not exist.


5 0
3 years ago
Read 2 more answers
X-2=3(x-4) what is the solution
Vladimir [108]
First distribute 3 to (x-4). that gives you 3x-12. Now your equation is x-2=3x-12. Now you subtract x from 3x. now you're equation is -2=2x-12. then add 12 to the left. You're final answer is 10.
8 0
3 years ago
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At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T
elixir [45]

Answer:

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

\text{Area of circle}=\pi r^2, where r represents radius of the circle.

\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2

\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2

\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

Therefore, the exact area of the side walk is 40 \pi\text{ m}^2

To find the approximate area of side walk let us substitute pi equals 3.14.

\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2

\text{Approximate area of the sidewalk}=125.6\text{ m}^2

Therefore, the approximate area of the side walk is 125.6\text{ m}^2.

5 0
3 years ago
Please solve this literal equation for the variable "f"
Tatiana [17]
\frac{df+10}{6}= g

Now, multiply both sides by 6 and you get.....

 df+10=6g

now, subtract 10 on both sides and you get.....

df=6g-10

now divide both sides by d to get f by itself and you get........

f= \frac{6g-10}{d}

8 0
3 years ago
What is the value of x?<br> 40<br> 550<br> A. 1059<br> B. 75°<br> C. 850<br> D. 95°
antoniya [11.8K]

Answer:

the answer is 85° because all angles in a triangle add up to 180

so u add them both up, subtract from 180 n u get 85

6 0
2 years ago
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