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Dmitry [639]
3 years ago
15

5.If 30mL of 0.5M NaOH(aq) was used to neutralize 10mL of HCl(aq), what is the concentration of the acid? Show work.

Chemistry
1 answer:
Zolol [24]3 years ago
7 0

Answer:

0.15M

Explanation:

NaOH + HCl -->NaCl + H2O

moles of NaOH reacted with HCl

(0.5 × 30)/1000 = 1.5 × 10^ -3

so the moles of HCl reacted with NaOH

1.5 × 10^ -3

concentration of HCl = ( 1.5 × 10^ -3)/10 ×1000

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3 0
3 years ago
A chemist measures the enthalpy change ?H during the following reaction: Fe (s) + 2HCl (g) ? FeCl2 (s) + H2 (g) =?H?157.kJ Use t
erik [133]

Correct Question:

A chemist measures the enthalpy change ΔH during the following reaction: Fe(s) + 2HCl(g)-->FeCl2(s) + H2 ΔH=-157.0 kJ. Use this information to complete the table below. Round each of your answers to the nearest kJ/mol

Answer:

-314 kJ

+628 kJ

+157 kJ

Explanation:

The enthalpy change of a reaction measures the amount of heat that is lost or gained by it. If ΔH >0 the heat is gained, and the reaction is called endothermic, if ΔH<0, the heat is lost, and the reaction is called exothermic.

If the reaction is inverted, the value of ΔH is inverted too (the opposite endothermic reaction is exothermic), and if the reaction is multiplied by a constant, ΔH will be multiplied by it too.

1) 2Fe(s) + 4HCl --> 2FeCl2(s) + 2H2(g)

This reaction is the product of the given reaction by 2, so

ΔH = 2*(-157) = -314 kJ

2) 4FeCl2(s) + 4H2(g) --> 4Fe(s) + 8HCl(g)

This reaction is the inverted reaction given multiplied by 4, so

ΔH = 4*(157) = +628 kJ

3) FeCl2(s) + H2(g) --> Fe(s) + 2HCl

This reaction is the inverted reaction given, so

ΔH = +157 kJ

4 0
3 years ago
If a block has the mass of 15.00 grams and measurements of 5.00cm by 3.00cm by 2.00cm what is the volume of the block?
Natalija [7]

Answer:

Volume = 30cm³

Explanation:

A block is a geometrical figure and its volume, -look at the figure-, follows the equation:

Volume = Width*Length*Height

As the measurements of the block are 5.00cm, 3.00cm and 2.00cm, the volume is:

Volume = 5.00cm*2.00cm*3.00cm

<h3>Volume = 30cm³</h3>

3 0
3 years ago
Mass divided by volume *
lorasvet [3.4K]
D — density

hope this helps !
5 0
3 years ago
How many grams are in 44.8 liters of nitrogen gas, n2?<br> a) 56g<br> b) 27g<br> c) 36g<br> d) 112g
kkurt [141]

a) 56g

<h3>Calculation:</h3>

At STP,

22.4 L of N₂ = 1 mol

We have given 44.8 L of N₂, therefore,

44.8 L of N₂ = \frac{44.8}{22.4}

                    = 2 mol

We know that,

1 mol of N₂ = 28 g

Hence,

2 mol of N₂ = 28 × 2

                   = 56g

Hence, there are 56 g of N₂ in 44.8 L of nitrogen gas.

Learn more about calculation at STP here:

brainly.com/question/9509278

#SPJ4

3 0
2 years ago
Read 2 more answers
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