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3 years ago

5.If 30mL of 0.5M NaOH(aq) was used to neutralize 10mL of HCl(aq), what is the concentration of the acid? Show work.

Chemistry

1 answer:

Zolol [24]3 years ago

7 0

Answer:

0.15M

Explanation:

NaOH + HCl -->NaCl + H2O

moles of NaOH reacted with HCl

(0.5 × 30)/1000 = 1.5 × 10^ -3

so the moles of HCl reacted with NaOH

1.5 × 10^ -3

concentration of HCl = ( 1.5 × 10^ -3)/10 ×1000

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How much heat is absorbed/released when 20.00 g of NH3(g) reacts in the presence of excess O2 (g) to produce NO (g) and H2O (l)

FrozenT [24]

Answer:

a. 342.9 kJ of heat are absorbed.

Explanation:

Calculation of the moles of $NH_3$ as:-

Mass = 20.00 g

Molar mass of $NH_3$ = 17.031 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{20.00\ g}{17.031\ g/mol}$

$Moles= 1.1743\ mol$

Given that:- $\Delta H=+1168\ kJ$

It means that 1 mole of $NH_3$ undergoes reaction and absorbs 1168\ kJ of heat

So,

1168 mole of $NH_3$ undergoes reaction and absorbs $1168\times 1168\ kJ$ of heat

<u>Amount of heat absorbed = + 342.9 KJ</u>

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3 years ago

If a can of soup 150 g mass and 0.75g/ cm^3 density what’s the volume

Liula [17]

Answer:

<h3>The answer is 200 cm³</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density}\\$

From the question

mass = 150 g

density = 0.75 g/cm³

We have

$volume = \frac{150}{0.75} \\$

We have the final answer as

Hope this helps you

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larisa86 [58]

Answer:

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Explanation:

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